The values of a and b are 4 & 6
2 out of 50 are defective.
Divide 2 by 50: 2/50 = 0.04
Now multiply the total quantity by that:
2000 x 0.04 = 80
80 are likely to be defective.
Log(2)/log(1.064) ≈ 11.17 . . . . hours
_____
The population can be given by
p(n) = p₀×1.064ⁿ . . . . where n is the number of hours
You want to find n whe p(n) = 2*p₀.
2p₀ = p₀×1.064ⁿ . . . . . . . . . . . . substitute the given information
2 = 1.064ⁿ . . . . . . . . . . . . . . . . . divide by p₀
log(2) = n×log(1.064) . . . . . . . . take logs to make it a linear equation
log(2)/log(1.064) = n . . . . . . . . divide by the coefficient of n
Answer:
the difference is that the 2 extra LARGE containers weigh bigger than the
6 small ones
Step-by-step explanation:
I think the correct answer is c
