Answer:
a + b = 16 or -16.
Step-by-step explanation:
a - b = 4
ab = 60 so a = 60/b
Substituting for a in the first equation:
60/b - b = 4
60 - b^2 = 4b
b^2 + 4b - 60 = 0
(b + 10)b - 6) = 0
b = 6, -10.
Therefore, from the first equation:
When b = -10 . a + 10 =4 giving a = -6 or
When b = 6, a - 6 = 4 giving a = 10.
So when a = -6, b = -10 and
when a = 10, b = 6.
So a + b is either 16 or -16.
<h3>
Explanation:</h3>
Class boundaries need to be defined so that a point on the boundary is unambiguously placed in one class or the other. With these boundaries, a value of 120 might be placed in the first or the second class—<em>we don't know which</em>.
_____
It is customary to define class boundaries between data values 60.5–120.5, for example, so that no data value can fall on the boundary, or as a semi-open interval [60, 120), so that a boundary value is clearly placed into a specific class.
Answer:
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Step-by-step explanation:
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value of x = 20 and value of y=16
Solution set=(20,16)
Step-by-step explanation:
We need to solve system of equations:
Let:
Simplifying equation 2:
Taking LCM on left side:
Adding eq(1) and eq(3)
Putting value of x in eq(1) and finding y:
So, value of x = 20 and value of y=16
Solution set=(20,16)
Keywords: System of equations
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