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SVETLANKA909090 [29]
3 years ago
15

Translate the sentence into an equality

Mathematics
1 answer:
Nata [24]3 years ago
6 0

A number x: x

Increased by 8: x+8

Is greater than or equal to..: x+8\geq \ldots

23: x+8 \geq 23

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Can you get a picture please or more detail...

4 0
3 years ago
Read 2 more answers
Suppose that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another br
Lina20 [59]

Answer:

The differential equation for the amount of salt A(t) in the tank at a time  t > 0 is \frac{dA}{dt}=12 - \frac{2A(t)}{500+t}.

Step-by-step explanation:

We are given that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another brine solution is pumped into the tank at a rate of 3 gal/min, and when the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

The concentration of the solution entering is 4 lb/gal.

Firstly, as we know that the rate of change in the amount of salt with respect to time is given by;

\frac{dA}{dt}= \text{R}_i_n - \text{R}_o_u_t

where, \text{R}_i_n = concentration of salt in the inflow \times input rate of brine solution

and \text{R}_o_u_t = concentration of salt in the outflow \times outflow rate of brine solution

So, \text{R}_i_n = 4 lb/gal \times 3 gal/min = 12 lb/gal

Now, the rate of accumulation = Rate of input of solution - Rate of output of solution

                                                = 3 gal/min - 2 gal/min

                                                = 1 gal/min.

It is stated that a large mixing tank initially holds 500 gallons of water, so after t minutes it will hold (500 + t) gallons in the tank.

So, \text{R}_o_u_t = concentration of salt in the outflow \times outflow rate of brine solution

             = \frac{A(t)}{500+t} \text{ lb/gal } \times 2 \text{ gal/min} = \frac{2A(t)}{500+t} \text{ lb/min }

Now, the differential equation for the amount of salt A(t) in the tank at a time  t > 0 is given by;

= \frac{dA}{dt}=12\text{ lb/min } - \frac{2A(t)}{500+t} \text{ lb/min }

or \frac{dA}{dt}=12 - \frac{2A(t)}{500+t}.

4 0
3 years ago
Absolute value inequality
Marizza181 [45]

|x| because just Google it if I'm wrong

8 0
3 years ago
i live in a house that 3 metets below sea level go to school 5 meters above sea level how many meters do i go​
RideAnS [48]
3 meters below sea level represents a -3
From -3 to 0 is 3
3 + 5 above sea level = 8 meters
There are 8 meters between the house and the school
4 0
3 years ago
Solve the inequality 2(4x-3)>-3(3)+5x
Sholpan [36]

Answer:

x > -1\\

Step by step explanation:

~~~~~2(4x-3) > -3(3)+5x\\\\\implies 8x-6 > -9+5x\\\\\implies 8x > -9+6+5x\\\\\implies 8x > -3+5x\\\\\implies 8x -5x > -3\\\\\implies 3x > -3\\\\\implies x > -\dfrac 33\\\\\implies x > -1

5 0
2 years ago
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