Ask question

Ask question

All categories

love history [14]

3 years ago

11

Find the annual interest rate. Round your answer to the nearest hundredth of a percent. I=$160.67, P=$2000, t=8 months

1 answer:

FinnZ [79.3K]3 years ago

3 0

Let would be the annual interest rate such that,
I = P x r^t
For the 1st
160.67 = (2000) x r*8/12 ; r = 0.02277
The second case is just the same.

You might be interested in

1 nnnnnnnneeeeeeeeeeeed help

zavuch27 [327]

Answer is 84.86 cm^2

8 0

2 years ago

The steps below show the incomplete solution to find the value of y for the equation 4y − 2y − 4 = −1 + 13: Step 1: 4y − 2y − 4

Maurinko [17]

Answer:

You stopped at 2y-4=12

If we add same number to both sides the equation will remain true. For example if we have 5=5, and we add 7 to both sides, we get 12=12 which is also true. Now let's do this with our equation. Add 4 to both sides(to have only y on the left side). We get 2y=16, hence y=8.

Answer. 2y=16

3 0

3 years ago

Pedro fills a glass 2/4 full with orange juice write a fraction with a denominator of 6 that is greater than 2/4

Deffense [45]

A fraction with the denominator of 6 and is breather than 2/4 would be 5/6 or 4/6

8 0

3 years ago

Roger can type 1530 words in 1/2 hour. How many words can he type per<br> minute?<br> PLS HELP ME

Lera25 [3.4K]

Answer:

25.5

Step-by-step explanation:

1530 divided by 60 is 25.5 and 25.5 multiplied by 60 is 1530.

6 0

2 years ago

goblinko [34]

The coding of the statistic is used to make it easier to work with the large sunshine data set

The mean of the sunshine is 3.05 $\overline 6$

The standard deviation is approximately <u>18.184</u>

<u />

Reason:

The given parameters are;

The sample size, n = 3.

∑x = 947

Sample corrected sum of squares, Sₓₓ = 33,065.37

The mean and standard deviation = Required

Solution:

$Mean, \ \overline x = \dfrac{\sum x_i}{n}$

The mean of the daily total sunshine is therefore;

$Mean, \ \overline x = \dfrac{947}{30} \approx 31.5 \overline 6$

$s = \dfrac{x}{10 } - \dfrac{1}{10}$

$E(s) = \dfrac{Ex}{10 } - \dfrac{1}{10}$

$E(s) = \dfrac{31.5 \overline 6}{10 } - \dfrac{1}{10} = 3.05 \overline 6$

The mean ≈ 3.05 $\overline 6$

Alternatively

, $The \ mean \ of \ the \ daily \ total \ sunshine, \, s = \dfrac{31.5 \overline 6 - 1}{10 } = 3.05\overline 6$

The mean of the daily total sunshine, $\overline s$ ≈3.05 $\overline 6$

$Var(s) = Var \left(\dfrac{x}{10 } - \dfrac{1}{10} \right)$

$Var(s) = \left(\dfrac{1}{10}\right)^2 \times Var \left(x \right)$

Therefore;

$Var(s) = \left(\dfrac{1}{10}\right)^2 \times 33,065.37 = 330,6537$

Therefore;

$s = \sqrt{330.6537} \approx 18.184$

The standard deviation, $s_s$ ≈ <u>18.184</u>

Learn more about coding of statistic data here:

brainly.com/question/14837870

3 0

2 years ago