1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
love history [14]
3 years ago
11

Find the annual interest rate. Round your answer to the nearest hundredth of a percent. I=$160.67, P=$2000, t=8 months

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
3 0
Let would be the annual interest rate such that,
                              I = P x r^t
For the 1st
                            160.67 = (2000) x r*8/12    ; r = 0.02277
The second case is just  the same. 
You might be interested in
Use the function below to find f(-4).
Margaret [11]

Answer:

A

Step-by-step explanation:

f(x) = 2x

f(-4) = 2(-4) = -8

7 0
3 years ago
Can somebody tell me the answer to −5/8+(−3/4)
hoa [83]

Answer:

he

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
I really need help with distributive property
docker41 [41]

Answer:

To “distribute” means to divide something or give a share or part of something. According to the distributive property, multiplying the sum of two or more addends by a number will give the same result as multiplying each addend individually by the number and then adding the products together.

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
The ratio of irises to The ratio of irises to roses in Nikki's garden is 2:5. She currently has 25 roses. She is planning to add
denpristay [2]
If the proportion of iris to roses in Nikki's garden is 2: 5, it means that for 25 roses: (2/5) = (10/25). Therefore to maintain the proportion by adding 20 roses: (2/5) = (18/45). The number of irises after the addition of roses will be 10 + 18 = 28 irises.
5 0
3 years ago
The Board of Directors of a small company consists of five people. Two of those directors are considered "strong leaders". If th
Pavel [41]
1: 40%
2: 30%
3: 20%

If we know one of the succeeded, then 
1: 44.44%
2: 33.33%
3: 22.22%

If under the circumstance that they all fail to meet a strong leader, the board picks one of them at random,
1: 43.33%
2: 33.33%
3: 23.33%

The first person has a 2 in 5 chance of randomly getting a strong leader. If the first person doesn't find a strong leader, the second person has a 2/4 chance of getting a strong leader. If neither the first nor second person gets a strong leader, the third sales person has a 2/3 chance of getting a strong leader.

1: 2/5=40% Chance
2: (3/5)*(2/4)=30% Chance You have to take the probability the first rep failed to get a strong leader, then multiply by the probability the second rep gets a strong leader.
3: (3/5)*(2/4)*(2/3)=20% You have to take the probability both the other people failed, then multiply by the probability they succeeded.
7 0
3 years ago
Other questions:
  • A coffee pot holds 2 and 3/4 quarts of coffee. How much is this in cups?
    13·1 answer
  • Adventura needs to know animals weight in kilograms is 20 pounds is about 9 kilograms and a dog weighs 30 pounds use a ratio tab
    13·1 answer
  • Which one of the following illustrates the truth value of the given statements? A square root of 16 is 4, and the only square ro
    9·2 answers
  • If 3/4 are tulips, and there are 2/3 that are red tulips, what fraction of the tulips a re yellow.
    5·1 answer
  • Why 6:4 and 18:8 are not equivalent ratios
    13·2 answers
  • What does -11 - (-6) =
    12·1 answer
  • 5.<br> 10 in.<br> 6 in.<br> 14 in.<br> shaded area<br> base<br> 6.
    15·1 answer
  • Y + 4 = 14(x-12), determine the slope and the y-intercept.
    12·2 answers
  • You just obtained a credit card. You immediately purchase a stereo system for $200. your credit limit is $1000. Let's assume tha
    10·2 answers
  • Line e is a segment bisector of AB at point M. If AM = 4n-40 &amp; MB = 7(-2n+2), find the value of n.​
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!