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elixir [45]
3 years ago
9

If a factor of a polynomial p(x)=2​

Mathematics
1 answer:
Eduardwww [97]3 years ago
3 0
Geometric figure is: line.
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1
padilas [110]
Answer: B

Trust me I took the test right now
6 0
3 years ago
Will mark brainliest if answered correctly!
Dima020 [189]
<h3>Answer: </h3>

about 1.768 seconds

<h3>Explanation:</h3>

Since the phone is <em>dropped</em>, the first equation applies. The final height is assumed to be zero, so we have ...

... h(t) = 0 = -16t² +50

... 16t² = 50 . . . . . . . . add 16t²

... t² = 50/16 . . . . . . . . divide by 16

... t = √3.125 . . . . . . . take the square root

... t ≈ 1.768 . . . . . . . . round to milliseconds

5 0
3 years ago
2 Find the sum: 8 7 + - = ?​
alukav5142 [94]

Answer:

15

Step-by-step explanation:

dont change the 10 and whats 8 + 7

7 0
3 years ago
Read 2 more answers
There were three went on a hike. One was 2 3/4, MI long, and the other 1 1/2 and the last one 3 3/8. In decimals what was the to
lana66690 [7]
7 5/8 miles or in decimal form 7.625 miles

3 0
3 years ago
Please help with this and explain how to do it, I'll give 15 points
MrRissso [65]

Answer:

Option (4).

Step-by-step explanation:

Outer diameter of the hollow metallic ball = 10 centimeters

Outer radius of this ball = \frac{10}{2} = 5 cm

Volume of the outer ball V_{1} = \frac{4}{3}\pi (r)^3

                                         = \frac{4}{3}\pi (5)^3

Inner radius of the hollow metallic ball = (5 - 1) = 4 cm

Volume of the inner hollow ball V_{2} = \frac{4}{3}\pi (4)^3

Volume of the metal used in the metallic ball = V_{1}-V_{2}

                                                                           = \frac{4}{3}\pi (5)^3-\frac{4}{3}\pi (4)^{3}

                                                                           = \frac{4}{3}\pi [(5)^3-(4)^3]

Therefore, expression given in option (4) will be used to measure the volume of the hollow metallic ball.

8 0
3 years ago
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