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harkovskaia [24]
3 years ago
8

Are fractions 1/5, 5/5, and 5/1 equivalent?

Mathematics
2 answers:
VashaNatasha [74]3 years ago
5 0
1/5= 1/5
5/5= 1
5/1= 5

Therefore, they are not equivalent~
grin007 [14]3 years ago
3 0
No 1/5 = 1/5 5/5 = 1 and 5/1= 5
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3/4 is 75%

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What is the answer to 5x-7=13
liubo4ka [24]

Answer:

x=4

Step-by-step explanation:

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Jill invested $20,000 in an account that earned 5.5% annual interest, compounded annually. What is the value of this account aft
noname [10]

The value of this account in 10 years is given by the formula:

FV = P*(1+r)^t

where FV is the future value in the account after 10 years(to be calculated)

P is the principal invested at the beginning

r is the interest rate and

t is the time horizon in years

Given, Invested Amount (P) = 20,000

Interest rate (r) = 5.5% = 0.055

Time horizon (t) = 10 years = 10

Substituting the formula, FV = 20,000*(1+0.055)^10 = 20,000*1.055^10 = 20,000*1.708144458 =  34,162.89

The value of this account after 10 years =$34,162.89 (Rounded to the nearest cent)

7 0
3 years ago
assume x and y are both differentiable functions of t. find dx/dt given x=-1 and dy/dt=8 for the relation: 4x^2+3y^3=28
melomori [17]

Given:

x and y are both differentiable functions of t.

4x^2+3y^3=28

x=-1\text{ and }\dfrac{dy}{dt}=8

To find:

The value of \dfrac{dx}{dt}.

Solution:

We have,

4x^2+3y^3=28       ...(i)

At x=-1,

4(-1)^2+3y^3=28

4+3y^3=28

3y^3=28-4

3y^3=24

Divide both sides by 3.

y^3=8

Taking cube root on both sides.

y=2

So, y=2 at x=-1.

Differentiate (i) with respect to t.

4(2x\dfrac{dx}{dt})+3(3y^2\dfrac{dy}{dt})=0

Putting x=-1, y=2 and \dfrac{dy}{dt}=8, we get

4(2(-1)\dfrac{dx}{dt})+3(3(2)^28)=0

-8\dfrac{dx}{dt}+9(4)(8)=0

-8(\dfrac{dx}{dt}-9(4))=0

Divide both sides by -8.

\dfrac{dx}{dt}-36=0

\dfrac{dx}{dt}=36

Therefore, the value of 4x^2+3y^3=28 is 36.

6 0
3 years ago
Select the correct answer!<br> Help asap thanks
tester [92]

The area of the shaded region is 3.125π - 6. The correct option is E. 3.125π - 6

<h3>Calculating area </h3>

From the question, we are to determine the area of the shaded region

The area of the shaded region = Area of the semicircle - Area of the triangle

First, we will determine the diameter, d, of the semicircle

d² = 3² + 4² (<em>Pythagorean theorem</em>)

d² = 9 + 16

d² = 25

d = √25

d = 5

∴ Diameter of the semicircle is 5

Thus,

Radius, r = 5/2 = 2.5

Now,

Area of the shaded region = 1/2(π×2.5²) - 1/2(3×4)

Area of the shaded region = 1/2(π×6.25) - 1/2(12)

Area of the shaded region = 3.125π - 6

Hence, the area of the shaded region is 3.125π - 6. The correct option is E. 3.125π - 6

Learn more on Calculating area here: brainly.com/question/14989383

#SPJ1

7 0
2 years ago
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