3 years ago

Please help!! :( if yah want brianleist!! Tyyyy!!! ^^

Mathematics

1 answer:

laila [671]3 years ago

6 0

Answer:

Step-by-step explanation:

hope this helps !!

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A. Work of 5 Joules is done in stretching a spring from its natural length to 16 cm beyond its natural length. What is the force

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Answer:

(a) 62.5 N

(b) 694.4 N/m

Step-by-step explanation:

Work done in stretching a spring is

$W = \frac{1}{2}Fe=\frac{1}{2}ke^2$ since $F=ke$

F is the applied force, E is the elongation and k is the spring constant.

(a) Here, e = 16 cm = 0.16 m

$W = \frac{1}{2}Fe$

$F = \dfrac{2W}{e} = \dfrac{2\times5}{0.16}=62.5\text{ N}$

(b) Here, e = 12 cm = 0.12 m

$W =\frac{1}{2}ke^2$

$k=\dfrac{2W}{e^2}=\dfrac{2\times5}{0.12^2}=694.4\text{ N/m}$

$F = \dfrac{2W}{e} = \dfrac{2\times5}{0.12}=41.7\text{ N}$

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5(3x + 5)<br><br> ( Please Help )

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A train leaves Little Rock, Arkansas, and travels north at 70 kilometers per hour. Another train leaves at the same time and tr

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