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NARA [144]
3 years ago
13

A box has 1 red marble, 3 blue marbles, and 4 green marbles. Maya draws a blue marble randomly from the box, replaces it, and th

en draws another marble randomly. What is the probability of drawing 2 blue marbles in a row? Explain your answer.
Mathematics
1 answer:
allochka39001 [22]3 years ago
6 0

Answer:

\dfrac{9}{64}

Step-by-step explanation:

Sampling with replacement means that we choose a marble, note its colour, put it back and shake the box, then choose a marble again.

There are 1+3+4=8 marbles in total. The probability that the first chosen marble is blue is \dfrac{3}{8}. then Maya replaces this marble and the probability of choosing the second blue marble is the same. Using the product rule, the probability of drawing 2 blue marbles in a row is

\dfrac{3}{8}\cdot \dfrac{3}{8}=\dfrac{9}{64}.

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Step-by-step explanation:

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Xy - 11 = 5 show the direct variation expalin your reasoning
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Cody is twice as old Evan and five years ago the sum of their age was 14. Find the age of each boy
Pani-rosa [81]
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3 years ago
Insert parenthesis in the following problem to make it true.
suter [353]

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6 0
3 years ago
p varies jointly as q and the square of r, and p = 200 when q = 2 and r = 3. Find p when q = 5 and r= 2.
Margarita [4]

Step-by-step explanation:

If a variables varies jointly, we can just divide it by the other variables in relation to it.

For example, since p variables jointly as q and square of r, then

\frac{p}{q {r}^{2} }  = k

where k is a constant

First, let find k. Substitute p= 200

q= 2, and r=3.

\frac{200}{2(3) {}^{2} }  = k

\frac{200}{18}  = k

\frac{100}{9}  = k

Now, since we know our constant, let find p.

\frac{p}{q {r}^{2} }  =  \frac{100}{9}

Q is 5, and r is 2.

\frac{p}{5( {2}^{2}) }  =  \frac{100}{9}

\frac{p}{20}  =  \frac{100}{9}

p =  \frac{2000}{9}

3 0
2 years ago
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