All categories

3 years ago

What are 4 things that can happen to a light wave when it hits an object?

Physics

2 answers:

fredd [130]3 years ago

8 0

Explanation:

The four things that can happen to a light wave when it hits an objects are :

1. Reflection : The bouncing back of light when the light wave strikes on a surface is called reflection of light.

2. Refraction : The bending of light when the light wave moves from one medium to another.

3. Absorption : Absorption is the process in which the light wave do not reflect back. It stays inside the material.

4. Transmission : Transmission of light is the process in which light wave goes continuously straight.

Some other process that are shown by a light wave are polarization, scattering etc.

mezya [45]3 years ago

4 0

Four different things can happen when light hits an object
The waves can be reflected or scattered off the object. 
The waves can be absorbed by the object. 
The waves can be refracted through the object. 
The waves can pass through the object with no effect.

You might be interested in

At room temperature what is the strength of the electric field in a 12-gauge copper wire (diameter 2.05 mm that is needed to cau

Dima020 [189]

Electric field strength = resistivity of copper x current density
where
p= 1.72 x 10^-8 ohm meter
diameter = 2.05mm=.00205 m
current = 2.75 A
get first the current density:
current density = current/ cross section area
find the cross section area
cross section area = pi.(d/2)^2;
cross section = 3.3 006x10-6 m^2
substitute the values
current density = 2.75A/3.3006x 10-6m^2
current density=35.55 x1 0^2 A/m^2
Electric field stregnth =1.72 x 10^-8 ohm meter x 35.55 x10^2 A/m^2
Electric field stregnth= 46.415 Volts/m

The electric field strength of copper is 46.415 V/m.

6 0

4 years ago

An object with a velocity of

algol [13]

Answer:

v = 1.7 m/s

Explanation:

Given that,

Initial velocity of the object, u = 1 m/s

Acceleration of the object, a = 1 m/s²

We need to find the velocity of the object after moving 1 m. Let v be the velocity. Using third equation of kinematics to find it i.e.

$v^2-u^2=2ad\\\\v^2=2ad+u^2\\\\v^2=2(1)(1)+1^2\\\\v=\sqrt3\\\\v=1.7\ m/s$

So, the final velocity of the object is 1.7 m/s.

4 0

4 years ago

One block rests upon a horizontal surface. A second identical block rests upon the first one. The coefficient of static friction

goblinko [34]

Answer:

The magnitud of the force is 124.8N.

Explanation:

First we have to find the value of the static friction coefficient, when the external force F is applied to upper block (i will call it A Block) we have a free body diagram as the one shown in the figure i attached, so since this block has no aceleration in any direction the force F should be equal to the friction force between A and B block, one we noticed this we can use the equation for the Friction force to find the coefficient:

$0=F-FrictionAB$

$F=FrictionAB=Nab*$ μs

and again, since the block has no acceleration the normal between A and B block should be equal to the weigth of the first block, so we have:

$0=Nab-W$

$Nab=W=mg$

replacing this we have:

$F=$ μs $*Nab=$ μs* $mg=41.6N$

and μs $=41.6N/(mg)$

now it's time to see the free body diagram for the b block, if we now apply the F force to the B block the diagram should look like in the figure.

the color of the arrow gives you an idea of where the force comes from, the blue ones comes from the B block, the red ones from the A block and the brown ones from the ground.

now for the B block you can see two friction forces, one for the ground and one for the A block, both of these directed bacwards, and two normal forces, again one for the ground and one for the A block but the normal force for the A block is aiming downwards.

again we use the fact that the block is not accelerating in any direction so the sum of the forces in x and y direction have to be 0, so:

$F-Friction1(ground)-Friction2(AB)=0$

This is the new external F force that we are looking for:

$F=Friction1(ground)+Friction2(AB)$

we know Friction2(AB) because we found that in the previous block so:

$F=Friction1(ground)+mg$ *μs

for the other friction we have to use the equation:

$Friction(ground)=N(ground)$ *μs

from y axis we have:

$N(ground)-w-Normal(AB)=0$

$N(ground)=w+Normal(AB)$

we found the value of Normal(AB) with the previous block so:

$N(ground)=mg+mg=2mg$

and:

$Friction(ground)=2mg$ *μs

$F=Friction(ground)+mg$ *μs

$F=2mg$ *μs+μs* $mg=3mg$ *μs

and since: μs* $mg=41.6N$

the new F force would be:

$F=3mg$ *μs $=41.6*3=124.8N$

4 0

3 years ago

What three factors control the path of a surface current

KATRIN_1 [288]

Answer:

Surface currents are controlled by three factors: global winds, the Coriolis effect, and continental deflections. surface create surface currents in the ocean. Different winds cause currents to flow in different directions. objects from a straight path due to the Earth's rotation.

Explanation:

3 0

3 years ago

A bug crawls 3.0 mm east, 4.0mm north, and then 5.0 mm at 45 north of east. Draw a diagram showing its displacements and determi

KatRina [158]

Answer:

Explanation is given

Mark Me as Branliest

3 0

3 years ago