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inessss [21]
3 years ago
11

During the last shot of the game, the basketball goes from rest to 15 m/s and reaches the backboard in 0.41 s. What was the acce

leration of the ball?
Physics
1 answer:
Anna [14]3 years ago
5 0

Answer: a= 37m

Explanation: V= 15 m/s (Velocity) t= 0.41s (time) formula: a= v/t

15 m/s / 0.41 (15 divided by 0.41) = 36.583m

There are 2 significant digits, 36, you look at the third digit, either round up or down in this case up to 36. a= 37m

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Why does the frequency of water increase as the wavelength decreases?
Oliga [24]

Answer:

Wave speed, frequency and wavelength in refraction

Explanation:

The diagram shows that as a wave travels into a denser medium, such as water, it slows down and the wavelength decreases. Although the wave slows down, its frequency remains the same, due to the fact that its wavelength is shorter. Hope this helps :>

5 0
3 years ago
Not a question but need a lot of tips
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8 0
3 years ago
Whqt do you mean by geo-stationery satellite? Explain.​
Ratling [72]

Answer:

Description: When a geosynchronous satellite is placed directly above the Equator with a circular orbit and angular velocity identical to that of the Earth, the satellite is known as a geostationary satellite

Explanation:

These satellites appear to be stationary above a particular point which is due to the synchronization. This type of satellite provides a distinct benefit of fixing the receiving antennas at one place, hence making them more economical than regular tracking antennas. Over the years, these satellites have helped in revolutionizing the global communications, weather forecasting and television broadcasting. When the orbit of a geosynchronous satellite is not aligned directly over the equator, the orbit is known as an inclined orbit.

8 0
3 years ago
A 20N net force acts upon an object with a mass of 4. 0kg. What is the object's acceleration?
galina1969 [7]

Answer:

5ms^-2

Explanation:

F = 20N, m = 4.0kg, a = ?

Using the formula for Force

F = ma

Then making acceleration the subject of the formula

a = F/m

a = 20N/4.0kg

a = 5ms^-2

8 0
2 years ago
The red light from a helium-neon laser has a wavelength of 721.4 nm in air. Find the speed, wavelength, and frequency of helium-
saveliy_v [14]

Answer:

(a) the speed of helium-neon laser light in air is 3 x 10⁸ m/s

     the wavelength of helium-neon laser light in air is 721.4 nm

     the frequency of helium-neon laser light in air is 415.86 THz

(b)  the speed of helium-neon laser light in water is 2.26 x 10⁸ m/s

     the wavelength of helium-neon laser light in water is  542.4nm

     the frequency of helium-neon laser light in water is    416.67THz

(c) the speed of helium-neon laser light in glass is 2 x 10⁸ m/s

    the wavelength of helium-neon laser light in glass is  480.9nm

    the frequency of helium-neon laser light in glass is  415.88THz

From the results above, it can be seen that speed of the light is directly proportional to its wavelength, while the frequency of the light remained fairly constant for the different media.

Explanation:

Part (a) the speed, wavelength, and frequency of helium-neon laser light in air

Given;

wavelength of helium-neon laser light in air, λ = 721.4 nm

speed of light in air, v = 3 x 10⁸ m/s

v = f λ

where;

f is the frequency of helium-neon laser light in air

f = \frac{v}{\lambda} = \frac{3*10^8}{721.4 *10^{-9}} =4.1586*10^{14} \ Hz

f = 415.86 THz

Part (b) the speed, wavelength, and frequency of helium-neon laser light in water

refractive index of water = 1.33

Refractive \ index \ of \ water =\frac{speed \ of \ light \ in \ air}{speed \ of \ light \ in \ water} = \frac{wavelength \ of \ light \ in \ air}{wavelength \ of \ light \ in \ water}

speed \ of \ light \ in \ water = \frac{speed \ of \ light \ in \ air}{Refractive \ index \ of \ water} \\\\speed \ of \ light \ in \ water = \frac{3*10^8}{1.33} = 2.26 *10^8 \ m/s

Again;

wavelength \ of \ light \ in \ water = \frac{wavelength \ of \ light \ in \ air}{Refractive \ index \ of \ water} \\\\wavelength \ of \ light \ in \ water = \frac{721.4 \ nm}{1.33} = 542.4 \ nm

f = \frac{v}{\lambda} = \frac{2.26*10^8}{542.4 *10^{-9}} =4.1667*10^{14} \ Hz

f = 416.67 THz

Part (c) the speed, wavelength, and frequency of helium-neon laser light in glass

Refractive index of glass = 1.5

speed \ of \ light \ in \ glass = \frac{speed \ of \ light \ in \ air}{Refractive \ index \ of \ glass} \\\\speed \ of \ light \ in \ glass = \frac{3*10^8}{1.5} = 2 *10^8 \ m/s

Also;

wavelength \ of \ light \ in \ glass = \frac{wavelength \ of \ light \ in \ air}{Refractive \ index \ of \ glass} \\\\wavelength \ of \ light \ in \ glass = \frac{721.4 \ nm }{1.5} = 480.9 \ nm

f = \frac{v}{\lambda} = \frac{2*10^8}{480.9 *10^{-9}} =4.1588*10^{14} \ Hz

f = 415.88 THz

5 0
3 years ago
Read 2 more answers
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