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Tasya [4]
3 years ago
6

A pressure of 10 MPa is applied to 0.25m3 of a liquid, causing a volume reduction of 0.005 cm3. Determine the bulk modulus of el

asticity.
Physics
1 answer:
Marina86 [1]3 years ago
6 0

Answer:

K = 500 x 10⁶ MPa

Explanation:

Given that

P = 10 MPa

V= 0.25 m ³

Reduction in the volume ,ΔV=- 0.005 cm³

We know that 1 m = 1000 cm

ΔV=- 0.005 cm³ = - 0.005  x 10⁻⁶ m³

We know that bulk modulus given as

K=-\dfrac{P}{\dfrac{\Delta V}{V}}

Now by putting the values

K=-\dfrac{10}{\dfrac{-0.005\times 10^{-6}}{0.25}}

We get

K = 500 x 10⁶ MPa

Therefore the bulk modulus of the elasticity will be 500 x 10⁶ MPa.

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Anna [14]

Answer:

Explanation:

In short, our atmosphere is here because of gravity. When Earth formed, about 4.5 billion years ago, the molten planet barely had an atmosphere. But as the world cooled, its atmosphere formed, largely from gases spewed out of volcanoes, according to the Smithsonian Environmental Research Center (SERC). This ancient atmosphere was very different from today's; it had hydrogen sulfide, methane and 10 to 200 times as much carbon dioxide as the modern atmosphere does, according to SERC. [Infographic: Earth's Atmosphere Top to Bottom]

7 0
3 years ago
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Ren runs a hamburger stand and needs to clean up a season’s worth of grease buildup on the range hood over his griddle. explain
baherus [9]
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4 years ago
A cylinder of mass 250 kg and radius 2.60 m is rotating at 4.00 rad/s on a frictionless.
aleksandrvk [35]

Answer:

The angular momentum of a cylinder, when it is rotating with constant angular velocity is Lini =Iωi

. When two cylinders are added to the rotating cylinder, which are identical in their dimensions, the moment of inertia of the entire system increases (since mass increases). The final moment of inertia will be 3I

Since friction exist, all the cylinders start rotating with same angular velocity, the new angular velocity can be calculated using conservation of angular momentum

Thus, Iωi =3Iωf ⟹ωf =ωi/3 = 0.33ωi

8 0
3 years ago
Your calculated density of aluminum is d = 2.76 g/cm3. Aluminum’s accepted density is 2.70 g/cm3. Without writing the "%" sign,
Rina8888 [55]

Answer:T he percentage error up to two decimal places is 2.22 %.

Explanation:

To calculate the percentage error, we use the equation:

\%\text{ error}=\frac{|\text{Experimental value - Accepted value}|}{\text{Accepted value}}\times 100

We are given:

Experimental value of density= 2.76g/cm^3

Accepted value of density = 2.70g/cm^3

\%\text{ error}=\frac{[{2.76 - 2.70}|}{2.70}\times 100=2.22%

Hence, the percentage error is 2.22 %.

3 0
3 years ago
A solenoid 91.0 cm long has a radius of 1.50 cm and a winding of 1300 turns; it carries a current of 3.60 A. Calculate the magni
irinina [24]

The magnitude of the magnetic field inside the solenoid is 6.46 \times 10^{-3} \ T.

The given parameters;

  • <em>length of the solenoid, L = 91 cm = 0.91 m</em>
  • <em>radius of the solenoid, r = 1.5 cm = 0.015 m</em>
  • <em>number of turns of the solenoid, N = 1300 </em>
  • <em>current in the solenoid, I = 3.6 A</em>

The magnitude of the magnetic field inside the solenoid is calculated as;

B = \mu_0 nI\\\\B = \mu_o(\frac{ N}{L} )I\\\\

where;

\mu_o is the permeability of frees space = 4π x 10⁻⁷ T.m/A

B = (4\pi \times 10^{-7}) \times (\frac{1300}{0.91} ) \times 3.6\\\\B = 6.46 \times 10^{-3} \ T

Thus, the magnitude of the magnetic field inside the solenoid is 6.46 \times 10^{-3} \ T.

Learn more here:brainly.com/question/17137684

7 0
2 years ago
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