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Tasya [4]
3 years ago
6

A pressure of 10 MPa is applied to 0.25m3 of a liquid, causing a volume reduction of 0.005 cm3. Determine the bulk modulus of el

asticity.
Physics
1 answer:
Marina86 [1]3 years ago
6 0

Answer:

K = 500 x 10⁶ MPa

Explanation:

Given that

P = 10 MPa

V= 0.25 m ³

Reduction in the volume ,ΔV=- 0.005 cm³

We know that 1 m = 1000 cm

ΔV=- 0.005 cm³ = - 0.005  x 10⁻⁶ m³

We know that bulk modulus given as

K=-\dfrac{P}{\dfrac{\Delta V}{V}}

Now by putting the values

K=-\dfrac{10}{\dfrac{-0.005\times 10^{-6}}{0.25}}

We get

K = 500 x 10⁶ MPa

Therefore the bulk modulus of the elasticity will be 500 x 10⁶ MPa.

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Explanation:

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3 0
3 years ago
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A uniform electric field of magnitude 4.6 ✕ 104 N/C is perpendicular to a square sheet with sides 3.0 m long. What is the electr
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Explanation:

given:

E= 4.6 * 10^4 N/C

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then electric flux = ∫ E*n dA

                            = ∫ 4.6 * 10^4 * 3*3

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4 years ago
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Fatima is watching her pet cat, Winter, napping in the sun. Fatima is curious about the heart rate of Winter when she is napping
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Explanation:

There are two hypotheses she could test:

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A wave travels at 175 m/s along the x-axis.If the period of the periodic vibrations of the wave is 3.00 milliseconds,then what i
OlgaM077 [116]

Answer:  

<h2>E) 52.5 cm</h2>

Explanation:

Step one:

given data

period T= 3 milliseconds= 0.003

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Step two:

we know that f=1/T

the expression relating period and wave lenght is

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to cm= 0.525*100

=52.5cm

The wavelength of the wave is E) 52.5 cm

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