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3 years ago

Why do circuits need to maintain a closed loop?

Physics

1 answer:

ivann1987 [24]3 years ago

8 0

Answer:

A closed circuit, for most intents and purposes, is one which carries electrons at high voltage through a load and releases them to an area of lower voltage. An open circuit is any circuit with a resistance sufficient to reduce the current to below any meaningful amount

Explanation:

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If a diode at 300°K with a constant bias current of 100μA has a forward voltage of 700mV across it, what will the voltage drop a

MAVERICK [17]

Answer:

the voltage drop across this same diode will be 760 mV

Explanation:

Given that:

Temperature T = 300°K

current $I_1$ = 100 μA

current $I_2$ = 1 mA

forward voltage $V_r$ = 700 mV = 0.7 V

To objective is to find the voltage drop across this same diode if the bias current is increased to 1mA.

Using the formula:

$I = I_o \begin {pmatrix} e^{\dfrac{V_r}{nv_T}-1} \end {pmatrix}$

$I_1 = I_o \begin {pmatrix} e^{\dfrac{V_r}{nv_T}-1} \end {pmatrix}$

where;

$V_r$ = 0.7

$I_1 = I_o \begin {pmatrix} e^{\dfrac{0.7}{nv_T}-1} \end {pmatrix}$

$I_2 = I_o \begin {pmatrix} e^{\dfrac{V_r'}{nv_T}-1} \end {pmatrix}$

$\dfrac{I_1}{I_2} = \dfrac{ I_o \begin {pmatrix} e^{\dfrac{0.7}{nv_T}-1} \end {pmatrix} }{ I_o \begin {pmatrix} e^{\dfrac{V_r'}{nv_T}-1} \end {pmatrix} }$

$\dfrac{100 \ \mu A}{1 \ mA} = \dfrac{ \begin {pmatrix} e^{\dfrac{0.7}{nv_T}-1} \end {pmatrix} }{ \begin {pmatrix} e^{\dfrac{V_r'}{nv_T}-1} \end {pmatrix} }$

Suppose n = 1

$V_T = \dfrac{T}{11600} \\ \\ V_T = \dfrac{300}{11600} \\ \\ V_T = 25. 86 \ mV$

Then;

$e^{\dfrac{V_r'}{nv_T}-1} = 10 \begin {pmatrix} e ^{\dfrac{ 0.7} { nV_T} -1} \end {pmatrix}$

$e^{\dfrac{V_r'}{nv_T}-1} = 10 \begin {pmatrix} e ^{\dfrac{ 0.7} { 25.86} -1} \end {pmatrix}$

$e^{\dfrac{V_r'}{nv_T}-1} = 5.699 \times 10^{12}$

${e^\dfrac{V_r'}{nv_T}} = 5.7 \times 10^{12}$

${\dfrac{V_r'}{nv_T}} =log_{e ^{5.7 \times 10^{12}}}$

${\dfrac{V_r'}{nv_T}} =29.37$

$V_r'=29.37 \times nV_T$

$V_r'=29.37 \times 25.86$

$V_r'=759.5 \ mV$

$Vr' \simeq$ 760 mV

Thus, the voltage drop across this same diode will be 760 mV

3 0

3 years ago

A wave changing shape when passing through an opening is an example of what?

igomit [66]

It is diffraction !!

7 0

4 years ago

A 3-ton Toyota land cruiser travelled at a speed of 45m/s, collides with a 2- ton comfort taxi which was parked in front of the

Olin [163]

Answer:

v = 27 m/s

Explanation:

To find the speed of cars after the collision you take into account the momentum conservation law. Total momentum of both cars before the collision must be equal to the total momentum of both cars after the collision.

After the collision both cars traveled together, then you have:

$m_1v_1+m_2v_2=(m_1+m_2)v$ (1)

m1: mass of the Toyota = 3-ton = 3000 kg

m2: mass of the taxi = 2-ton = 2000kg

v1: speed of the Toyota before the collision = 45m/s

v2: speed of the car before the collision = 0 m/s (it is at rest)

v: speed of both cars after the collision = ?

You solve the equation (1) for v:

$v=\frac{m_1v_1+m_2v_2}{m_1+m_2}$

Next, you replace the values of the rest of the variables:

$v=\frac{(3000kg)(45m/s)+0kgm/s}{3000kg+2000kg}=27\frac{m}{s}$

hence, just after the collision both cars have a speed of 27m/s

7 0

3 years ago

. Set the applied force to Force necessary to Keep the box Moving without accelerating. Restart the animation. Just before the b

Arte-miy333 [17]

Answer:

elative magnitude of the two forces is the same and they are applied in a constant direction.

Explanation:

Newton's second law states that the sum of the forces is equal to the mass times the acceleration

∑ F = m a

in this case there are two forces on the x axis

F_applied - fr = 0

since they indicate that the velocity is constant, consequently

F_applied = fr

the relative magnitude of the two forces is the same and they are applied in a constant direction.

3 0

3 years ago

Which scientist was the first to use the telescope in astronomy

Mashutka [201]

Answer:

Galileo Galilei

Explanation:

although Galileo was not the scientist who invented the telescope, he was the first to use it to observe celestial objects. he used the telescope in 1609. his discovery included more accurate information about the moon, the sun and some of the planets.

4 0

3 years ago