Answer:
Domain → (-∞, -1)∪(-1, ∞)
Range → (-∞, ∞)
Step-by-step explanation:
Given function is,

This function is not defined when the denominator is zero.
2x + 2 = 0
2x = -2
x = -1
Therefore, x = -1 is not in the domain of this function.
And the domain will be,
(-∞, -1)∪(-1, ∞)
For all values of x (except x = -1) we get some output values (value of
).
Therefore, range of the function will be (-∞, ∞).
The diver's depth is 55.485 feet.
Option B represents the correct expression of the equation.
<h2>How do you express the given condition in an equation form?</h2>
Given that the total depth is 200 feet. the steady rate of the diver is 12 and one-third feet per minute. The total time taken by the diver is 4.5 minutes.
The above condition can be written in equation form is given below.
Total Depth = Steady Rate per Minute
Total Time


Hence we can conclude that option B represents the correct form of the equation.
To know more, follow the link given below.
brainly.com/question/7161930.
160•.60=96
160-96=64
the discount is 96 and the amount after the discount is 64 i think
<h2>
Hello!</h2>
The answer is: 
<h2>
Why?</h2>
Domain and range of trigonometric functions are already calculated, so let's discard one by one in order to find the correct answer.
The range is where the function can exist in the vertical axis when we assign values to the variable.
First:
: Incorrect, it does include 0.4 since the cosine range goes from -1 to 1 (-1 ≤ y ≤ 1)
Second:
: Incorrect, it also does include 0.4 since the cotangent range goes from is all the real numbers.
Third:
: Correct, the cosecant function is all the real numbers without the numbers included between -1 and 1 (y≤-1 or y≥1).
Fourth:
: Incorrect, the sine function range is equal to the cosine function range (-1 ≤ y ≤ 1).
I attached a pic of the csc function graphic where you can verify the answer!
Have a nice day!
Answer:
The mid-point between the endpoints (10,5) and (6,9) is:
Step-by-step explanation:
Let (x, y) be the mid-point
Given the points
Using the formula to find the mid-point between the endpoints (10,5) and (6,9)

Here:

Thus,



Therefore, the mid-point between the endpoints (10,5) and (6,9) is: