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8090 [49]
3 years ago
5

A new surgery is successful 75% of the time. if the results of 10 such surgeries are randomly sampled, what is the probability t

hat fewer than 9 of them are successful
Mathematics
1 answer:
valentinak56 [21]3 years ago
4 0
\text{Binomial Distribution: } P(X = r) = \binom{n}{r}(p)^{r}(1 - p)^{n - r}
P(X < 9) = 1 - P(X = 9) - P(x = 10)

P(X = 9) = \binom{10}{9}(0.75)^{9}(0.25)
P(X = 10) = \binom{10}{10}(0.75)^{10}

P(X < 9) = 1 - \binom{10}{9}(0.75)^{9}(0.25) - \binom{10}{10}(0.75)^{10}
\approx 0.755974769...
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