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miv72 [106K]
2 years ago
15

Trigonometry ratio of multiple angles​

Mathematics
1 answer:
lys-0071 [83]2 years ago
3 0

Answer:

See Attached

Step-by-step explanation:

See Attached for proof of RHS = LHS

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Pleas help! I think its A but I'm not sure! 50 points
DedPeter [7]

Answer:

x<-9

So C is correct answer

Step-by-step explanation:

-3x-7<20

-3x<20+7

-3x<27

x<27/-3

x<-9

6 0
2 years ago
Read 2 more answers
Identify the sequence graphed below and the average rate of change from n = 1 to n = 3. coordinate plane showing the point 2, 10
Katena32 [7]

Answer:

  • geometric sequence with initial value 20 and common ratio 1/2
  • average rate of change on [1, 3] = -7.5

Step-by-step explanation:

(a) The given points have sequential values of x and values of y that are each 1/2 the value before. The common ratio tells us the sequence is a geometric sequence.

(b) The first given point is (2, 10), so extrapolating backward, we determine the previous point to be ...

... (2-1, 10/(1/2)) = (1, 20)

Thus, we have enough information to determine the average slope between n=1 and n=3.

... (difference in y)/(difference in n) = (5 -20)/(3 -1) = -15/2 = -7.5

4 0
3 years ago
Sont answer if u don't have a answer ​
Readme [11.4K]

Answer:

no association because there is no specific pattern

7 0
2 years ago
Read 2 more answers
If 0° ≤ θ ≤ 90° and cosθ = 11/15 , what is the value of sin (90° - θ)?
igor_vitrenko [27]
11/15=0.7333
cos^{-1}(0.7333) =42.83342
sin(90-47.166572) = 0.7333

first, find the numeric value for 11/15
second to find theta, simply do the <em>inverse</em> cos (which is cos^-1) of the first answer.
now you know theta, just do the sin of 90 - theta and that's it!

since you know whatr cos(theta) is, you just take the inverse cos of that number to get theta and 'reverse' cos, essentially. you are just solving for theta, by reversing the cos function with cos^-1
please mark as brainliest!
7 0
3 years ago
Read 2 more answers
Pls tell me step by step how to do this
kap26 [50]

it is 43.35 or 20.95


5 0
3 years ago
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