Answer:
(0, 1)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y + 5x = 1
5y - x = 5
<u>Step 2: Rewrite Systems</u>
y + 5x = 1
- Subtract 5x on both sides: y = 1 - 5x
<u>Step 3: Redefine Systems</u>
y = 1 - 5x
5y - x = 5
<u>Step 4: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitution in <em>y</em>: 5(1 - 5x) - x = 5
- Distribute 5: 5 - 25x - x = 5
- Combine like terms: 5 - 26x = 5
- Isolate <em>x</em> term: -26x = 0
- Isolate <em>x</em>: x = 0
<u>Step 5: Solve for </u><em><u>y</u></em>
- Define equation: 5y - x = 5
- Substitute in <em>x</em>: 5y - 0 = 5
- Subtract: 5y = 5
- Isolate <em>y</em>: y = 1
Answer:
28.25
Step-by-step explanation:
First simplifying step by step.
<span>16x^5+12xy-9y^5
Answer is = </span><span><span><span>16<span>x^5</span></span>+<span><span>12x</span>y</span></span>+</span>−<span>9<span>y<span>5
It will help you.</span></span></span>
Answer:
y=2/3×+6
Step-by-step explanation:
y-2=2/3(×+6)
y=2/3x4+2
y=2/3×+6
Answer:
The probability is 0.694
Step-by-step explanation:
Let the probability of getting a car washed be
P(W) = 72% = 0.72
Let the probability of getting a car vacuumed be
P(V) = ?
Probability of getting car washed and vacuumed is P(W n V) = 50% = 0.5
From Bayes’ theorem
P(V|W) is the probability that a customer gets their car vacuumed given that they are getting it washed
So mathematically;
P(V|W) = P(V n W)/P(W)
= 0.5/0.72 = 0.694
