Starting with the point (-1, 4) and the slope m = -3, write out the point-slope equation of a straight line: y - k = m(x - h) becomes y - 4 = -3(x + 1), or:

y = -3x - 3 + 4

y = -3x + 1 This is the same as answer choice (b).

5 0

3 years ago

Math help please and thanks

Artyom0805 [142]

Answer:

idek and i dont ;like how this is working!

Step-by-step explanation:

5 0

2 years ago

Fernando puts 3 pictures on each page of his photo album. He puts pictures on 8 pages. Represent it by array.

lakkis [162]

X X X X X X X X
X X X X X X X X
X X X X X X X X

6 0

3 years ago

Read 2 more answers

The point (5,4) lies on a circle. what is the length of the radius of this circle if the center is located at (3,2)

Art [367]

Use the x and y values from your point and the h and k from the center to write the equation you need to solve for r. The general form of the equation for a circle is $(x-h) ^{2} +(y-k) ^{2} = r^{2}$ . We will fill in accordingly: $(5-3) ^{2}+(4-2) ^{2} = r^{2}$ . Solve for r to get that $r= \sqrt{8}$

4 0

3 years ago