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lisabon 2012 [21]
3 years ago
8

A publisher reports that 45% of their readers own a laptop. A marketing executive wants to test the claim that the percentage is

actually different from the reported percentage. A random sample of 190 found that 41% of the readers owned a laptop. Find the value of the test statistic. Round your answer to two decimal places.
Mathematics
1 answer:
mariarad [96]3 years ago
6 0

Answer:

-1.00

Step-by-step explanation:

Given that a  publisher reports that 45% of their readers own a laptop. A marketing executive wants to test the claim that the percentage is actually different from the reported percentage.

Sample size n =190

Sample proportion p = 0.41

H_0: p = 0.45\\H_a: p \neq 0.45

(Two tailed test )

Assuming H0 to be true

std error = \sqrt{pq/n} =\sqrt{0.45*0.55/155} \\=0.0400

p difference = -0.04

Test statistic = p differencce/std error

= -1

Hence test statistic is -1.00

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Slope of (0,45) (6,33) (15,15)
Vladimir [108]

Answer:

The slope is -2

Step-by-step explanation:

Given

(x_1,y_1) = (0,45)

(x_2,y_2) = (6,33)

(x_2,y_3) = (15,15)

Required

The slope (m)

Slope is calculated as:

m = \frac{y_2 -y_1}{x_2 - x_1}

So, we have:

m = \frac{33 -45}{6 - 0}

m = \frac{-12}{6}

m =-2

4 0
3 years ago
A husband and wife have normal vision, although both of the couple's fathers are red–green color-blind, an inherited X-linked re
Mekhanik [1.2K]

Answer:

1/2

Step-by-step explanation:

Since the recessive gene is carried in the x chromosome and a father can only pass it to a daughter, the father doesn't have the disease nor carries it.

The mother carries the recessive gene because her father passed her his conditioned gene (only having one x chromosome), while her mother gave her a normal one so she can have normal vision.  

The chance of having a boy or a girl is 1/2 and the chance of this baby of having both recessive gene is null because in order to have a girl that is color blind both her x chromosomes must have the recessive gene, but the father can't pass it since he doesn't carries it. Therefore the combined probability is 1/2*(1-0) = 1/2.

7 0
3 years ago
IM having trouble trying to solve this problem
Assoli18 [71]

Answer:

You would have approximately 201 insects.

Step-by-step explanation:

To calculate the final population of the insects, you need to first insert the values of each variable you know into the equation. The initial population at time t=0 would be 100 insects, the rate of population growth coverted to decimal form would be 0.1, and the elapsed time since time t=0 is 7 days. Now the new equation would be P = 100(e)^{0.1*7}.

   P = 100(e)^{0.1*7}

⇒ P ≈ 100 * 2.01

⇒ P ≈ 201

You will have 201 insects in 7 days (rounded to the nearest insect).

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