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lisabon 2012 [21]
3 years ago
8

A publisher reports that 45% of their readers own a laptop. A marketing executive wants to test the claim that the percentage is

actually different from the reported percentage. A random sample of 190 found that 41% of the readers owned a laptop. Find the value of the test statistic. Round your answer to two decimal places.
Mathematics
1 answer:
mariarad [96]3 years ago
6 0

Answer:

-1.00

Step-by-step explanation:

Given that a  publisher reports that 45% of their readers own a laptop. A marketing executive wants to test the claim that the percentage is actually different from the reported percentage.

Sample size n =190

Sample proportion p = 0.41

H_0: p = 0.45\\H_a: p \neq 0.45

(Two tailed test )

Assuming H0 to be true

std error = \sqrt{pq/n} =\sqrt{0.45*0.55/155} \\=0.0400

p difference = -0.04

Test statistic = p differencce/std error

= -1

Hence test statistic is -1.00

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Answer:

a) Josh likely made the negative and positive multiplication error.

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4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B125%20%7D%20-%20%5Csqrt%7B180%7D%20%2B%20%5Csqrt%7B45%7D%20" id="TexFormula1" tit
Kobotan [32]

Answer:

2\sqrt{5}

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

Simplifying the radicals

\sqrt{125} = \sqrt{25(5)} = \sqrt{25} × \sqrt{5} = 5\sqrt{5}

\sqrt{180} = \sqrt{36(5)} = \sqrt{36} × \sqrt{5} = 6\sqrt{5}

\sqrt{45} = \sqrt{9(5)} = \sqrt{9} × \sqrt{5} = 3\sqrt{5}

Thus

\sqrt{125} - \sqrt{180} +\sqrt{45}

= 5\sqrt{5} - 6\sqrt{5} + 3\sqrt{5}

= 2\sqrt{5}

3 0
3 years ago
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