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lisabon 2012 [21]

3 years ago

8

A publisher reports that 45% of their readers own a laptop. A marketing executive wants to test the claim that the percentage is

actually different from the reported percentage. A random sample of 190 found that 41% of the readers owned a laptop. Find the value of the test statistic. Round your answer to two decimal places.

1 answer:

mariarad [96]3 years ago

6 0

Answer:

-1.00

Step-by-step explanation:

Given that a publisher reports that 45% of their readers own a laptop. A marketing executive wants to test the claim that the percentage is actually different from the reported percentage.

Sample size n =190

Sample proportion p = 0.41

$H_0: p = 0.45\\H_a: p \neq 0.45$

(Two tailed test )

Assuming H0 to be true

std error = $\sqrt{pq/n} =\sqrt{0.45*0.55/155} \\=0.0400$

p difference = -0.04

Test statistic = p differencce/std error

= -1

Hence test statistic is -1.00

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475+498=973

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3 years ago

A student bought 3 shirts at $12.25 each and 2 pairs of pants at $25.50 each. How much money

4vir4ik [10]

Answer: 87.75

Step-by-step explanation:

Multiply 12.25 times 3 because the student bought 3 shirts

Then multiply 25.50 times 2 because the student bought two pairs of pants

Then add up both your multiplication together and you will get 87.75

3 0

3 years ago

A) Write the sequence of natural numbers which are multiplied by 3 ?

Volgvan

Answer:

a) 3, 6, 9, 12, 15,..., $3\cdot n$ , b) 4, 7, 10, 13, 16,..., $3\cdot n +1$ , c) Both sequences are arithmetic.

Step-by-step explanation:

a) The sequence of natural numbers which are multiplied by 3 are represented by the function $f(n) = 3\cdot n$ , $n\in \mathbb{N}$ . Let see the first five elements of the sequence: 3, 6, 9, 12, 15,...

b) The sequence of natural numbers which are multiplied by 3 and added to 1 is represented by the function $f(n) = 3\cdot n + 1$ , $n\in \mathbb{N}$ . Let see the first five elements of the sequence: 4, 7, 10, 13, 16,...

c) Both sequences since differences between consecutive elements is constant. Let prove this statement:

(i) $f(n) = 3\cdot n$

$\Delta f = f(n+1) -f(n)$

$\Delta f = 3\cdot (n+1) -3\cdot n$

$\Delta f = 3$

(ii) $f(n) = 3\cdot n +1$

$\Delta f = f(n+1)-f(n)$

$\Delta f = [3\cdot (n+1)+1]-(3\cdot n+1)$

$\Delta f = 3$

Both sequences are arithmetic.

8 0

3 years ago

A store is having a sale on jelly beans and trail mix. For 3 pounds of jelly beans and 2 pounds of trail mix, the total cost is

Nata [24]

the cost for each of jelly beans and each pound of trail mix is $2.5 and $1.75

<u>Step-by-step explanation:</u>

Given A store is having a sale on jelly beans and trail mix. For 3 pounds of jelly beans and 2 pounds of trail mix, the total cost is $11. For 5 pounds of jelly beans and 6 pounds of trail mix, the total cost is $23 . We have to find the cost for each pound of trail mix and each pound of jelly beans.

Let the cost of each pound of trail mix is $y.

and the cost of each pound of jelly beans is $x.

According to question,

For 3 pounds of jelly beans and 2 pounds of trail mix, the total cost is $11.

⇒ $3x+2y=11$ → (1)

For 5 pounds of jelly beans and 6 pounds of trail mix, the total cost is $23

⇒ $5x+6y=23$ → (2)

Solving (1) and (2), we get

3(1 equation)-(2 equation)=0

⇒ $3(3x+2y)-5x-6y=3(11)-23$

⇒ $9x+6y-5x-6y=10$

hence,

⇒ $4x=10$

⇒ $x=2.5$

Putting $x=2.5$ in $3x+2y=11$ we get ;

⇒ $3x+2y=11$

⇒ $3(2.5)+2y=11$

⇒ $2y=11-7.5=3.5$

⇒ $y=1.75$

Hence, the cost for each of jelly beans and each pound of trail mix is $2.5 and $1.75 .

6 0

4 years ago