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yawa3891 [41]
3 years ago
10

A 20.0-liter flask contains a mixture of argon at 0.72 atmosphere and oxygen at 1.65 atmospheres. What is the total pressure in

the flask?
Chemistry
1 answer:
GarryVolchara [31]3 years ago
3 0

The total pressure of the flask is sum of partial pressures of the gases present in a mixture of gas

This is Dalton's law of partial pressures .'

say we have a mixture of "n" gases with respective pressure : P1, P2 ...Pn

total pressure of the gases = P1 +P2 + P3 + ...Pn = Ptotal

So in the given problem the total pressure of flask will be = 0.72+1.65 = 2.37 atm

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Suppose 10.0 mL of 2.00 MNaOH is added to (a) 0.780 L of pure water and (b) 0.780 L of a buffer solution that is 0.682 Min butan
katrin2010 [14]

Answer:

a) pH will be 12.398

b) pH will be 4.82.

Explanation:

a) The moles of NaOH added = molarity X volume (L) = 2 X 0.01 = 0.02 moles

The total volume after addition of pure water = 0.780+0.01 = 0.79 L

The new concentration of /NaOH will be:

molarity=\frac{molesofsolute}{volumeofsolution}=\frac{0.02}{0.79}=0.025M

the [OH⁻] = 0.025

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pH = 14 -pOH = 12.398

b) The buffer has butanoic acid and butanoate ion.

i) Before addition of NaOH the pH will be calculated using Henderson Hassalbalch's equation:

pH=pKa+log\frac{[salt]}{[acid]}

pKa=-logKa=-log(1.5X10^{-5})=4.82

ii) on addition of base the pH will increase.

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4 years ago
What is the density of Iodine gas at 2.36 atm and 65.0 C?
timurjin [86]

The density : 21.63 g/L

<h3>Further explanation</h3>

The gas equation can be written  

\large {\boxed {\bold {PV = nRT}}}

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08206 L.atm / mol K  

T = temperature, Kelvin  

T = 65+273=338 K

P=2.36 atm

MW Iodine gas (I₂)=254

The density :

\tt \rho=\dfrac{P\times MW}{RT}\\\\\rho=\dfrac{2.36\times 254}{0.082\times 338}=21.63~g/L

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