Answer:
Explanation:
Each half life period reduced the amount of substance by half
So 6 of half life cycles or decays will go.
The most abundant alkali metal is *Sodium*
Answer:
19.5g
Explanation:
Given parameters:
Volume of propane gas = 9.95L
Unknown:
Mass of propane gas = ?
Solution:
To solve this problem, find the number of moles first.
At STP;
22.4L of gas makes up 1 mole
9.95L of gas will have a
= 0.44mole
So;
Mass of propane gas = number of moles x molar mass
Molar mass of propane = 3(12) + 8(1) = 44g/mol
Mass = 0.44 x 44 = 19.5g
Colligative
properties calculations are used for this type of problem. Calculations are as
follows:<span>
ΔT(freezing point) = (Kf)(molality)
ΔT(freezing point)
= 1.86 °C kg / mol (molality)
</span>Tf - 102.08 = 1.86m
Tf = 1.86m + 102.08
The concetration of the solution is needed in order to obtain a specific value.