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2 years ago

How did the different reform movements we've discussed change and shape America? Pls help

Chemistry

1 answer:

tigry1 [53]2 years ago

6 0

Answer:

ok ............bu am not so sure

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What is the relationship between the release of energy as heat and calories

Olegator [25]

Answer:

Explanation:

Calories is a unit to measure the amount of energy contained in a particular food product. It is regarded as the energy required to raise the temperature of 1g of water by 1°C.

It is important note that calories measures the heat content of food we eat and consume. Therefore, there is a direct relationship between the release of energy as heat and the calories. The more the calories, the more the energy that would be released as heat.

7 0

3 years ago

On Earth an object weighs 50 N. On Planet X, the object weighs 500 N. What conclusion can be drawn from these observations? A. P

inysia [295]

The gravitation field strength of Planet X is 10 times that of Earth's, as the object weight has increased 10 times. This is only possible if the planet is more massive or more dense (smaller diameter).

Therefore, the answer is C.

7 0

3 years ago

A substance is tested and has a pH of 1.2. How would you classify it?

djyliett [7]

Answer:

A weak acid

Explanation:

Im not sure if its right. But lets see someone else do it.

6 0

2 years ago

Read 2 more answers

Given a solution with a Ph of 2.8, what is the [H3O+] of the solution?

Crank

$pH=-\log_{10} [H_3O^+] \Rightarrow [H_3O^+]=10^{-pH} \\ \\
pH=2.8 \\
\ [H_3O^+]=10^{-2.8} \approx 1.58 \times 10^{-3}$

The [H₃O⁺] of the solution is approximately 1.58 × 10⁻³ M.

6 0

3 years ago

You are given 25.00 mL of an acetic acid solution of unknown concentration. You find it requires 35.75 mL of a 0.2750 M NaOH sol

oksano4ka [1.4K]

Answer:

a. 0.393M CH₃COOH.

b. 2.360% of acetic acid in the solution

Explanation:

The reaction of acetic acid (CH₃COOH) with NaOH is:

CH₃COOH + NaOH → CH₃COO⁻ + H₂O + Na⁺

<em>That means 1 mole of acid reacts per mole of NaOH.</em>

Moles of NaOH to reach the equivalence point are:

35.75mL = 0.03575L × (0.2750mol / L) = <em>9.831x10⁻³ moles of NaOH</em>

As 1 mole of acid reacts per mole of NaOH, moles of CH₃COOH in the acid solution are 9.831x10⁻³ moles.

a. As the volume of the acetic acid solution is 25.00mL = 0.02500L, the molarity of the solution is:

9.831x10⁻³ moles / 0.02500L =

b. Molar mass of acetic acid is 60g/mol. The mass of 9.831x10⁻³ moles is:

9.831x10⁻³ moles ₓ (60g / mol) = <em>0.590g of CH₃COOH</em>.

As volume of the solution is 25.00mL, the percentage of acetic acid is:

(0.590g CH₃COOH / 25.00mL) ₓ 100 =

<h3>2.360% of acetic acid in the solution</h3>

8 0

3 years ago