Carbon atoms present in 2. 00 g of butane is 8.28 × 10^22.
Molecular weight of C4H10 is = 58.1 grams
Moles of butane = given mass/ molar mass
= 2/58.1
= 0.0344 mol
Multiply the number of moles by Avogadro's number. This will let you obtain the number of butane molecules:
0.0344 x 6.023 x 10^{23} molecules of butane = 2.07 × 10^22 molecules
of butane
Now multiply this number by four (due to four carbon atoms per butane molecule) to obtain the answer:
so, no. of carbon atoms = 4 x 2.07x 10^22 = 8.28x 10^22 atoms.
Thus the no. of carbon atom is 8.28×10^22.
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A volatile impurity, is an impurity that evaporates quickly, so, if you were to conduct an experiment on a substance with this type of impurity, the evaporation point, and the mass of the substance at high temperatures would be in error.
Answer:
Explanation:
Percent yield is the ratio of the amount actually produced to how much could theoretically be produced. It is found using this formula:
For this reaction, the theoretical or expected yield is 325.0 grams. The actual yield is 123.8 grams.
Divide.
Round to the nearest hundredth. The 9 in the hundredth place tells us to round the 0 to a 1 .
The percent yield is about <u>38.1%</u>
A plasma is a hot ionized gas consisting of approximately equal numbers of positively charged ions and negatively charged electrons. The characteristics of plasmas are significantly different from those of ordinary neutral gases so that plasmas are considered a distinct "fourth state of matter
Their are 18 covalent bonds in a molecule of cyclohexane
