Supposing, for the sake of illustration, that the mean is 31.2 and the std. dev. is 1.9.
This probability can be calculated by finding z-scores and their corresponding areas under the std. normal curve. 34 in - 31.2 in The area under this curve to the left of z = -------------------- = 1.47 (for 34 in) 1.9 32 in - 31.2 in and that to the left of 32 in is z = ---------------------- = 0.421 1.9
Know how to use a table of z-scores to find these two areas? If not, let me know and I'll go over that with you.
My TI-83 calculator provided the following result:
normalcdf(32, 34, 31.2, 1.9) = 0.267 (answer to this sample problem)
Two equations with infinite solutions would look the exact same. Example: y=mx+b y=mx+b Example 2 y=2x+5 y=2x+5 For an equation with no solution they would have the same slope but different y intercepts. An equation with same slope and same y intercepts would have infinite solutions.
