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Marysya12 [62]
3 years ago
14

Click on the graphic below until RA TU at point Q is displayed. Plzzzzz help

Mathematics
2 answers:
andre [41]3 years ago
5 0

Answer:

I think its

             T

 R--------Q----------A

             U

Step-by-step explanation:

Because RA as a line bisects TU

KatRina [158]3 years ago
4 0

Answer:

not sure

Step-by-step explanation:

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For the answer to the question above, 
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<span>1 + nx + [n(n-1)/(2 x 1)](x)^2 + [n(n-1)(n-2)/3 x 2 x 1] (x)^3 </span>

<span>1 + nx + [n(n-1)/2](x)^2 + [n(n-1)(n-2)/6] (x)^3 </span>

<span>1 + 9x + 36x^2 + 84x^3 </span>

<span>In my experience, up to the x^3 is often adequate to approximate a route. </span>

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<span>x = 0.98 - 1 = -0.02 </span>

<span>Substituting: </span>

<span>1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 </span>

<span>approximation = 0.834 </span>

<span>Checking the real value in your calculator: </span>

<span>(0.98)^9 = 0.834 </span>

<span>So you have approximated correctly. </span>

<span>If you want to know how accurate your approximation is, write out the result of each in full: </span>

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3 years ago
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Which of the following represents the zeros of f(x)=3x^3-10x^2-81x 28? Answer choices: A.) 7, -4,1/3 B.) 7,-4, -1/3 C.) 7,4,1/3
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<span>The right function is f(x)=3x^3-10x^2-81x + 28

You can realize that 7 is a root because it is in all the answers.

So you can divide the polynomial by x - 7. If you do it you can find that the quotient is 3x^2 + 11x - 4

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If you do it, you will find they are x = 1/3 and x = -4.

So the answer is option A) 7, -4, 1/3

And the polynomial can be written as (x - 7)(x + 4) (x -1/3)
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