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aalyn [17]
3 years ago
8

PLEASE HELP ! Will reward brainliest

Mathematics
1 answer:
klasskru [66]3 years ago
7 0
<span>To find the union of the two sets simply write all of the elements together into one big set. Remove any duplicate entries (if there are any).</span>

A \cup B = \{x,y,z,a,b,c\}

--------------------------------------------------------------

The intersection of the two sets A and B is the set of elements that are in BOTH sets. In this case, there is no overlap so we have

A \cap B = \{ \} = \varnothing
which is a way of saying "the empty set"


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Is ∞ the same as +∞?
dezoksy [38]

Answer:

infinity and positive infinity are the same

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3 years ago
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If one-third of a number, x, is greater than five less than twice the number, which of the following is true?
MakcuM [25]

Answer:

x= 15/7

Step-by-step explanation:

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3 years ago
Sea un cuadrado de 2 pulgadas de lado uniendo los puntos medios se obtiene otro cuadrado inscrito en el anterior si repetimos es
Ne4ueva [31]

Answer:

1) La serie geométrica formada es

4, 2, 1,..., ∞

2) La suma al infinito de las áreas de los cuadrados es 8 in.²

Step-by-step explanation:

1) El área del primer cuadrado, a₁ = 2² = 4 pulgadas²

El área del siguiente cuadrado, a₂ = (√ (1² + 1²)) ² = (√2) ² = 2 pulg²

El área del siguiente cuadrado, a₃ = ((√ (2) / 2) ² + (√ (2) / 2) ²) = 1 pulg²

Por lo tanto, la razón común, r = a₂ / a₁ = 2/4 = a₃ / a₂ = 1/2

Las áreas de los cuadrados progresivos forman una progresión geométrica como sigue;

4, 4×(1/2), 4 ×(1/2)²,...,4×(1/2)^{\infty}

De donde obtenemos la serie geométrica formada de la siguiente manera;

4, 2, 1,..., ∞

2) La suma de 'n' términos de una progresión geométrica hasta el infinito para -1 <r <1 se da como sigue;

S_{\infty} = \dfrac{a}{1 - r}

Por lo tanto, la suma de las áreas de los cuadrados hasta el infinito se obtiene sustituyendo los valores de 'a' y 'r' en la ecuación anterior de la siguiente manera;

La \ suma \ al \ infinito \ del \ cuadrado \ S_{\infty}  = \dfrac{4 \ in.^2}{1 - \dfrac{1}{2} } = \dfrac{4 \ in.^2}{\left(\dfrac{1}{2} \right)} = 2 \times 4 \ in.^2= 8 \ in.^2

La suma al infinito de las áreas de los cuadrados, S_{\infty} = 8 in.²

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2 years ago
A team has P points.
stich3 [128]
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3 years ago
What's the answer to this?
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