<u>Answer:</u>
Factor over complex numbers of 
is 
<u>Solution: </u>
From question given that
→ (1)
On substituting 
in equation (1),
Taking 2 as a common in above expression,
Rewrite the above expression,
![=2\left[y^{2}+2(y)(9)+9^{2}\right]](https://tex.z-dn.net/?f=%3D2%5Cleft%5By%5E%7B2%7D%2B2%28y%29%289%29%2B9%5E%7B2%7D%5Cright%5D)
![\left[\text { Using }(a+b)^{2}=a^{2}+2 a b+b^{2}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Ctext%20%7B%20Using%20%7D%28a%2Bb%29%5E%7B2%7D%3Da%5E%7B2%7D%2B2%20a%20b%2Bb%5E%7B2%7D%5Cright%5D)
![\left[\text { since } y=x^{2}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Ctext%20%7B%20since%20%7D%20y%3Dx%5E%7B2%7D%5Cright%5D)
![\left[\text { Using } a^{2}+b^{2}=(a+i b)(a-i b), \text { where } i=\sqrt{-1}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Ctext%20%7B%20Using%20%7D%20a%5E%7B2%7D%2Bb%5E%7B2%7D%3D%28a%2Bi%20b%29%28a-i%20b%29%2C%20%5Ctext%20%7B%20where%20%7D%20i%3D%5Csqrt%7B-1%7D%5Cright%5D)
![=2[(x+3 i)(x-3 i)]^{2}](https://tex.z-dn.net/?f=%3D2%5B%28x%2B3%20i%29%28x-3%20i%29%5D%5E%7B2%7D)
Hence Factor over complex numbers of is
Jane is 12 years old and Harvey is 36.
Attached a solution and showed work.
Answer:
$125
Step-by-step explanation:
11,000 - 9,500 = 1,500
1,500 / 12 = 125 (we use 12 because 12 months = 1 year)
Answer:
corrcet answer is 140
Step-by-step explanation:
b-12= 18
b = 30
4(30+5)
4(35)
140
can i get brainliest.
