Which of the following represents the zeros of f(x)=3x^3-10x^2-81x 28? Answer choices: A.) 7, -4,1/3 B.) 7,-4, -1/3 C.) 7,4,1/3
D.) 7,4,-1/3
1 answer:
<span>The right function is f(x)=3x^3-10x^2-81x + 28
You can realize that 7 is a root because it is in all the answers.
So you can divide the polynomial by x - 7. If you do it you can find that the quotient is 3x^2 + 11x - 4
Now you can use the quadratic formula to find the other two roots.
If you do it, you will find they are x = 1/3 and x = -4.
So the answer is option A) 7, -4, 1/3
And the polynomial can be written as (x - 7)(x + 4) (x -1/3)
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Answer:
20
Step-by-step explanation:
Sin = opposite/hyp
Sin A = 10/26 = 5/13
Sin b = 24/26 = 12/13
The answer is option A
Hope this helps
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Answer:
Quotient = 18
Remainder = 10
Step-by-step explanation:
1234/68
=> 68 x 1 = 68
=> 123 - 68 = 55
=> Take the 4 down
=> 554/68
=> 68 x 8 = 544
=> 554 - 544 = 10
So, the quotient = 18.
Remainder = 10
<h3>
Answer:</h3>
- y = -(x -3)² +3 . . . . (agrees with your answer)
- see the attachment for a graph
<h3>
Step-by-step explanation:</h3>
Factoring the leading -1 from the first two terms, we have ...
... y = -(x² -6x) -6
Adding 9 inside parentheses to complete the square, then adding the opposite amount outside parentheses, we have ...
... y = -(x² -6x +9) -6 +9
... y = -(x -3)² +3
