Answer:
Explanation:
i )
When it is disconnected with the battery , the charge stored in it becomes fixed . When the plate distance becomes half , its capacitance becomes twice from C to 2C . Let charge stored in it at the time of disconnection from battery be Q . Let plate separation reduces from d to d / 2
So charged stored in it will remain unchanged .
ii )
Potential difference = charge / capacitance
in the first case potential difference = Q / C
in the second case potential difference = Q / 2C
So potential difference becomes half .
iii ) electric field = potential diff / plate separation
in the first case electric field = Q / (d x C )
in the second case electric field = 2 Q / (d x 2C)
= Q / (d x C )
So electric field remains unchanged .
iv)
energy stored in first case = Q² / 2C
In the second case energy stored = Q² / 2x2C
so energy stored becomes half .
Answer:

Explanation:
From the question we are told that:
Acceleration 
Displacement 
Initial time 
Final Time 
Generally the equation for Velocity of 1.05 travel is mathematically given by
Using Newton's Law of Motion



Generally the equation for Distance traveled before stop is mathematically given by



Generally the equation for Distance to stop is mathematically given by
Since For this Final section
Final velocity 
Initial velocity 
Therefore
Using Newton's Law of Motion


Giving

Therefore



Generally the Total Distance Traveled is mathematically given by



Answer:
30 degrees
Explanation:
Reflects off of mirror 1 at 60 degrees....this makes it incident to second mirror at 30 degrees ....then angle of reflection equals this angle of incidence = 30 degrees
See atached diagram
Answer: An electric motor
Explanation:
I took the quiz for physics and this was the answer
Asterism, a pattern of stars that is not a constellation. An asterism can be part of a constellation, such as the Big Dipper, which is in the constellation Ursa Major, and can even span across constellations, such as the Summer Triangle, which is formed by the three bright stars Deneb, Altair, and Vega.