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4 years ago

A wire carrying an electric current is often likened to a pipe carrying water. What part of this analogy is incorrect?

1 answer:

6 0

In a direct current (DC) electrical circuit, the voltage (V in volts) is an expression of the available energy per unit charge which drives the electric current (I in amperes) around a closed circuit. Increasing the resistance (R in ohms) will proportionately decrease the current which may be driven through the circuit by the voltage.

Each quantity and each operational relationship in a battery-operated DC circuit has a direct analog in the water circuit. The nature of the analogies can help develop an understanding of the quantities in basic electric ciruits. In the water circuit, the pressure P drives the water around the closed loop of pipe at a certain volume flow rate F. If the resistance to flow R is increased, then the volume flow rate decreases proportionately. You may click any component or any relationship to explore the the details of the analogy with a DC electric circuit.

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How do I calculate speed, velocity, and acceleration? I need the formulas too

vodomira [7]

Speed is the secular unit, which means it only measures "how fast it goes."
$speed= \frac{distance}{time}$
Velocity is a victory unit, which means it measures "both how fast it goes AND the direction."
$velocity= displacement/time$
Acceleration is the change of velocity over time.
$acceleration = \frac{change in velocity}{time}$

5 0

3 years ago

A student throws a ball upward with a velocity of 35 m/s. What is the acceleration of the ball as it rises to the top of its arc

lora16 [44]

Answer:

The acceleration of the ball as it rises to the top of its arc equals 9.807 meters per square second.

Explanation:

Let suppose that maximum height of the arc is so small in comparison with the radius of the Earth.

Since the ball is launched upwards, then the ball experiments a free-fall motion, that is, an uniform accelerated motion in which the element is accelerated by gravity. Then, the acceleration experimented by the motion remains constant at every instant and position.

Besides, the gravitational acceleration in the Earth and, in consequence, the acceleration of the ball as it rises to the top of its arc equals 9.807 meters per square second.

7 0

3 years ago

An electron is accelerqated in the uniform field betwen two parallel charged oplates. The separation of the plates is 1.20 cm

marysya [2.9K]

Answer:

The speed of electron is $8.7\times10^{6}\ m/s$

Explanation:

Given that,

Separation of the plate = 1.20 cm

Suppose the field is $E=1.80\times10^{4}\ N/C$ .

If the electron is accelerated from rest near the negative plate and passes through a tiny hole in the positive plate.

What the speed does it leave the hole?

We need to calculate the acceleration

Using formula of electric force

$F = qE$

$ma=qE$

$a=\dfrac{qE}{m}$

We need to calculate the speed of electron

Using equation of motion

$v^2=u^2+2as$

$v^2=2as$

Put the value of acceleration in the formula

$v^2=2\times\dfrac{qE}{m}\times s$

Put the value into the formula

$v^2=2\times\dfrac{1.6\times10^{-19}\times1.80\times10^{4}\times1.20\times10^{-2}}{9.11\times10^{-31}}$

$v=\sqrt{2\times\dfrac{1.6\times10^{-19}\times1.80\times10^{4}\times1.20\times10^{-2}}{9.11\times10^{-31}}}$

$v=8.7\times10^{6}\ m/s$

Hence, The speed of electron is $8.7\times10^{6}\ m/s$

7 0

3 years ago

Use the SI prefixes in Table 3 of this chapter to convert these hypothetical units of measure into appropriate quantities: a. 10

Amanda [17]

<span>The first response would be "deca," since this is a multiple of 10^1. B, since it's working off the thousands prefix (10^3), would be "kilo." The third, at 10^-6, would be "micro." Next, at 10^-9, would be "nano," and the final, 10^18, would have a prefix of "exa."</span>

6 0

4 years ago

I need the answer to this question please

Mandarinka [93]

Answer:

tanong mo kay gugel..wag dito nabobobo ako

6 0

3 years ago