What happens to momentum when two objects collide
1 answer:
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Answer:
a. S(t)=350−1t
Explanation:
To determine the equation of motion you take into account the general form of motion with constant velocity:
( 1 )
So is the initial position from a specific reference frame. In this case is 350 m.
v is the speed of the motion, in this case is 1m/s. However, the motion is forward the zero point of the reference frame, hence, the speed is - 1m/s.
You replace the values of So and v in the equation ( 1 ) and you obtain:
Hence, the answer is:
a. S(t)=350−1t
- - - - - - - - - - - - - - - - - - - - -
Para determinar a equação do movimento, você leva em consideração a forma geral do movimento com velocidade constante:
(1)
Assim é a posição inicial de um quadro de referência específico. Neste caso, é de 350 m.
v é a velocidade do movimento, neste caso é de 1m / s. No entanto, o movimento é avançar o ponto zero do quadro de referência, portanto, a velocidade é de - 1m / s.
Você substitui os valores de So ev na equação (1) e obtém:
Portanto, a resposta é:
uma. S (t) = 350-1t, movimento retrógrado
Answer:
(a) 19.71801m/s Velocity just before going up the ramp.
(b) 74.56338m.
Explanation:
We will solve it in two parts, first we will calculate time that 5kg wooden block would take to just reach ramp and with this time we will calculate final velocity that the wooden block would have in this time.
Second, we will calculate the component of velocity vector along inclined plane and the time that it would take for velocity to be 0 meters/s then with this time we will calculate the distance that inclined plane would travel along inclined plane.
Following formulas will be used.
(a) Calculating velocity right before going up the ramp.
Wooden block is going on a straightaway and has net for on it.
=
and this force produces acceleration of
With this acceleration, wooden block would reach at the foot of ramp in.
and final velocity will be
this velocity of wooden box just before going up the ramp.
(b) How far up the ramp will the wooden block go before stopping.
Ramp is at 20° relative to horizontal therefore velocity along the ramp that the wooden block would have will be.
and deceleration along the ramp is
Where force of friction along the inclined plane.
is a component of g along normal of the inclined plane.
And with this deceleration time needed to get wooded block to stop is.
and in that time wooden block would travel
This is how up wooden box will go before coming to stop.