Answer:
The horizontal distance the package traveled while falling, S = 197.99 m
Explanation:
Given,
The horizontal velocity of the helicopter, v = 70 m/s
The time taken by the package to fall into the water is, t = 8.0 s
The initial horizontal component of velocity, Vx = 70 m/s
The initial vertical component of velocity, Vy = 0 m/s
The time of flight is given by the formula
Since Vy = 0 ; solving for h
h = gt²/2 meter
Substituting the given values in the above equation
h = (9.8 x 8²) / 2
= 39.2 m
The horizontal distance traveled while falling is given by the formula
Since, Vy = 0, equation becomes
Substituting the values in the above equation
S = 197.99 m
Hence, the horizontal distance the package travels while falling is, S = 197.99 m