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nlexa [21]
3 years ago
9

When does the edge of the water advance farther inland- when the ocean's floor is a gradual slope or steep slope?

Physics
1 answer:
Blababa [14]3 years ago
3 0

Answer:

The correct answer is when the slope is steep.

Explanation:

The advancement of water inland is dependent on the rate at which water wears off the continental shelf and the coastal plain. The higher the amount of rainfall, and the harshness of the dry spells, the faster the rate of erosion that occurs at the coastal plain.

As the erosion increases, the coastal plain becomes steeper. The steeper the plain, the water flowing erodes the coastal plain at a faster rate. Hence the water advances farther inland faster than where the slope is gentle or gradual.

Cheers

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Calculate the angle of refraction of 30.0° light shines from water into ice. The indices of refraction for water and ice are 1.3
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Answer:

The angle of refraction Ø2 equals 62.95° ≈ 63°

Explanation:

The relationship between the angles of incidence and

refraction , with respect to light or other waves passing through two different substances or media, such as glass, water or air is given by Snell's Law.

Snell's Law states that the when light travels from one medium to another, it generally refracts.

It is given by the mathematical expression;

[SinØ1°/SinØ2°] = [n2/n1]

Cross multiplying, we have;

n1 × SinØ1° = n2 × SinØ2°

where, n is the indices of refraction of each substance

Ø is the angle between the ray and the line normal to the surface.

Given the following values;

n1 = 1.36 n2 = 1.31 Ø1 = 30° Ø = ?

n1 × SinØ1° = n1 × SinØ2°

SinØ2° = [n1 × SinØ1°]/n2

substituting the values respectively;

SinØ2° = [1.36 × Sin30°]/1.31

SinØ2° = [1.36 × 0.5]/1.31

SinØ2° = 0.68 × 1.31

SinØ2° = 0.8906

Ø2° = Sin–¹(0.8906)

Ø2° = 62.95° ≈ 63°

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Answer:

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Answer:

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