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3241004551 [841]
3 years ago
13

The three main types of nuclear radiation are alpha, beta, and gamma

Physics
2 answers:
harina [27]3 years ago
7 0
Answer:

Gamma, beta, alpha

Explanation:

Gamma rays have the shortest wavelengths of all electromagnetic radiation, has the greatest penetrating power. Gamma rays can pass completely through the human body; as they pass through, they can cause ionizations that damage tissue and DNA. Then Beta particles are more penetrating than alpha particles, but can be stopped by a thin sheet of aluminum.
valkas [14]3 years ago
6 0

Answer:

Gamma beta alpha

Explanation:

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The work done when a force moves a body through a distance of 15m is 1800j. What is the value of the force applied
Leviafan [203]

Answer:

120

Work :

W = Fd (work = force x distance)

Force :

F = W/d

Distance :

d = W/F

7 0
3 years ago
A 25.0 g marble sliding to the right at 20.0 cm/s overtakes and collides elastically with a 10.0 g marble moving in the same dir
ikadub [295]
In collision that are categorized as elastic, the total kinetic energy of the system is preserved such that,

   KE1  = KE2

The kinetic energy of the system before the collision is solved below.

  KE1 = (0.5)(25)(20)² + (0.5)(10g)(15)²
  KE1 = 6125 g cm²/s²

This value should also be equal to KE2, which can be calculated using the conditions after the collision.

KE2 = 6125 g cm²/s² = (0.5)(10)(22.1)² + (0.5)(25)(x²)

The value of x from the equation is 17.16 cm/s.

Hence, the answer is 17.16 cm/s. 
6 0
3 years ago
Which of the following would NOT produce a current? A. Moving a bar magnet inside a coil of wire O B. Moving a bar magnet toward
sineoko [7]

Answer:

c

Explanation:

7 0
3 years ago
(c) If η = 60% and TC = 40°F, what is TH, in °F?
arlik [135]
2b2t hope that helps
5 0
3 years ago
When the mass is removed, the length of the cable is found to be l0 = 4.66 m. After the mass is added, the length is remeasured
zaharov [31]

Answer:

\gamma=6.07*10^5\frac{N}{m^2}

Explanation:

For a linear elastic material Young's modulus is a constant that is given by:

\gamma=\frac{F/A}{\Delta L/L_0}

Here, F is the force exerted on an object under tensio, A is the area of the cross-section perpendicular to the applied force, \Delta L is the amount by which the length of the object changes and  L_0 is the original length of the object. In this case the force is the weight of the mass:

F=mg\\F=55kg(9.8\frac{m}{s^2})\\F=539N

Replacing the given values in Young's modulus formula:

\gamma=\frac{F/\pi r^2}{(L_1-L_0)/L_0}\\\gamma=\frac{539N/\pi(0.045m)^2}{(5.31m-4.66m)/4.66m}\\\gamma=6.07*10^5\frac{N}{m^2}

6 0
3 years ago
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