All categories

4 years ago

I do not understand this

Mathematics

2 answers:

enot [183]4 years ago

8 0

I think it is c but I don't knowb

Contact [7]4 years ago

7 0

If you want to shift the graph of a function horizontally left, then you add some amount to the x-value. If a horizontal right shift is needed, then you subtract from the x-value.

Furthermore, if you wish to move your graph vertically up, then add to the y-value (the function itself). And subtract from it for a vertically down shift.

Now, we need a horizontal 3 unit left shift. That means we add 3 to the x-value, without touching the function itself. The function is $\mathrm{F}(x)=x^2$ , hence the shifted function is $\mathrm{G}(x)=(x+3)^2$ .

You might be interested in

Suppose there are 4 defective batteries in a drawer with 10 batteries in it. A sample of 3 is taken at random without replacemen

SSSSS [86.1K]

Answer:

a.) 0.5

b.) 0.66

c.) 0.83

Step-by-step explanation:

As given,

Total Number of Batteries in the drawer = 10

Total Number of defective Batteries in the drawer = 4

⇒Total Number of non - defective Batteries in the drawer = 10 - 4 = 6

Now,

As, a sample of 3 is taken at random without replacement.

a.)

Getting exactly one defective battery means -

1 - from defective battery

2 - from non-defective battery

So,

Getting exactly 1 defective battery = ⁴C₁ × ⁶C₂ = $\frac{4!}{1! (4 - 1 )!}$ × $\frac{6!}{2! (6 - 2 )!}$

= $\frac{4!}{(3)!}$ × $\frac{6!}{2! (4)!}$

= $\frac{4.3!}{(3)!}$ × $\frac{6.5.4!}{2! (4)!}$

= $4$ × $\frac{6.5}{2.1! }$

= $4$ × $15$ = 60

Total Number of possibility = ¹⁰C₃ = $\frac{10!}{3! (10-3)!}$

= $\frac{10!}{3! (7)!}$

= $\frac{10.9.8.7!}{3! (7)!}$

= $\frac{10.9.8}{3.2.1!}$

= 120

So, probability = $\frac{60}{120} = \frac{1}{2} = 0.5$

b.)

at most one defective battery :

⇒either the defective battery is 1 or 0

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 0 , then 3 non defective

Possibility = ⁴C₀ × ⁶C₃

= $\frac{4!}{0! (4 - 0)!}$ × $\frac{6!}{3! (6 - 3)!}$

= $\frac{4!}{(4)!}$ × $\frac{6!}{3! (3)!}$

= 1 × $\frac{6.5.4.3!}{3.2.1! (3)!}$

= 1× $\frac{6.5.4}{3.2.1! }$

= 1 × 20 = 20

getting at most 1 defective battery = 60 + 20 = 80

Probability = $\frac{80}{120} = \frac{8}{12} = 0.66$

c.)

at least one defective battery :

⇒either the defective battery is 1 or 2 or 3

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 2 , then 1 non defective

Possibility = ⁴C₂ × ⁶C₁

= $\frac{4!}{2! (4 - 2)!}$ × $\frac{6!}{1! (6 - 1)!}$

= $\frac{4!}{2! (2)!}$ × $\frac{6!}{1! (5)!}$

= $\frac{4.3.2!}{2! (2)!}$ × $\frac{6.5!}{1! (5)!}$

= $\frac{4.3}{2.1!}$ × $\frac{6}{1}$

= 6 × 6 = 36

If the defective battery is 3 , then 0 non defective

Possibility = ⁴C₃ × ⁶C₀

= $\frac{4!}{3! (4 - 3)!}$ × $\frac{6!}{0! (6 - 0)!}$

= $\frac{4!}{3! (1)!}$ × $\frac{6!}{(6)!}$

= $\frac{4.3!}{3!}$ × 1

= 4×1 = 4

getting at most 1 defective battery = 60 + 36 + 4 = 100

Probability = $\frac{100}{120} = \frac{10}{12} = 0.83$

3 0

3 years ago

Y = 5x + 7 2x + y = -5 Are the equations parallel, perpendicular, or neither?

Nezavi [6.7K]

Lines are neither perpendicular nor parallel.

Step-by-step explanation:

Step 1:

In equation 1, Y = 5X + 7

In equation 2, Y = -2X -5

Step 2:

Slope Intercept form Y =mX +c

Where m = Slope

Slope of line 1 = 5

Slope of line 2 = -2

m1 is not equal to m2. Hence it is not parallel.

m1 × m2 is not equal to -1. Hence they are not perpendicular.

3 0

4 years ago

If anybody could help with this question I would appreciate it so much!!

elena-14-01-66 [18.8K]

Answer:

d=7

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Can you please show work please

-BARSIC- [3]

Answer:

1) y = 3x+5

2) y = $\frac{1}{2}x-4$

3) y = -x + 0

4) y = $-\frac{5}{3}x+8$

5) y = $\frac{3}{5} x - 7$

Step-by-step explanation:

y = mx+b

In slope-intercept form, these are important to know:

- y and x should stay as variables

- m = slope of the line

- b = y intercept

Using the facts above⬆, we can solve these problems

Remember: Substitute m and b using the given information

1) y = 3x+5

2) y = $\frac{1}{2}x-4$

3) y = -x + 0

4) y = $-\frac{5}{3}x+8$

5) y = $\frac{3}{5} x - 7$

Hope this helps :)

Have a great day!

3 0

2 years ago

A herd of dinosaurs made paintings in the sand with their claws. Each baby dinosaur made 1515 paintings and each adult dinosaur

mart [117]

Answer:

4 adult dinosaurs and 12 baby dinosaurs.

Step-by-step explanation:

Let the number of adult dinosaurs be x.

Number of baby dinosaurs = 3x

Number of paintings made by each baby dinosaur = 15

Number of paintings made by each adult dinosaur = 7

Total number of paintings made by 3x baby dinosaurs = Number of baby dinosaurs * Number of paintings made by each baby dinosaur

= 3x * 15

= 45x

Total number of paintings made by x adult dinosaurs = Number of adult dinosaurs * Number of paintings made by each adult dinosaur

= x * 7

= 7x

Total number of paintings made by both baby and adult dinosaurs = 45x + 7x

= 52 x

Again the problem says that the total number of paintings made = 208

So, 52x = 208

Dividing both sides by 52

$\frac{52x}{52}$ = $\frac{208}{52}$

Cancelling out the 52's from the top and bottom on the left

x = 4

So, number of adult dinosaurs = 4

Number of baby dinosaurs = 3x = 3*4 = 12

8 0

3 years ago