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Ganezh [65]
4 years ago
9

I do not understand this

Mathematics
2 answers:
enot [183]4 years ago
8 0
I think it is c but I don't knowb
Contact [7]4 years ago
7 0

If you want to shift the graph of a function <em>horizontally left</em>, then you <em>add</em> some amount to the x-value. If a <em>horizontal right</em> shift is needed, then you <em>subtract</em> from the x-value.

Furthermore, if you wish to move your graph <em>vertically up</em>, then <em>add</em> to the y-value (the function itself). And <em>subtract</em> from it for a <em>vertically down</em> shift.

Now, we need a <em>horizontal </em><u><em>3</em></u><em> unit left</em> shift. That means we <em>add </em><u><em>3</em></u> to the x-value, without touching the function itself. The function is \mathrm{F}(x)=x^2, hence the shifted function is \mathrm{G}(x)=(x+3)^2.

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X-y+z=-4<br><br> 3x+2y-z=5<br><br> -2x+3y-z=15<br><br> How do I solve this?
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1)\ \ \ x-y+z=-4\ \ \ \Rightarrow\ \ \ z=-4-x+y\\\\2)\ \ \ 3x+2y-z=5 \\.\ \ \ \  \Rightarrow\ \ 3x+2y-(-4-x+y)=5 \\.\ \ \ \  \Rightarrow\ \ 3x+2y+4+x-y=5 \\.\ \ \ \  \Rightarrow\ \ 4x+y=1\\\\3)\ \ \ -2x+3y-z=15\\.\ \ \ \  \Rightarrow\ \ -2x+3y-(-4-x+y)=15\\.\ \ \ \  \Rightarrow\ \ -2x+3y+4+x-y=15\\.\ \ \ \  \Rightarrow\ \ -x+2y=11\\--------------------\\

z=-4-x+y\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ and\\ \left \{ {{4x+y=1\ \ \ \ } \atop {-x+2y=11\ /\cdot4}} \right. \\\\\left \{ {{4x+y=1\ \ \ \ } \atop {-4x+8y=44}} \right. \\-------\\y+8y=1+44\\9y=45\ /:9\\y=5\\\\-x+2y=11\ \ \ \Rightarrow\ \ \ x=2y-11\ \ \ \Rightarrow\ \ \ x=2\cdot5-11=-1\\\\z=-4-x+y=-4-(-1)+5=-4+1+5=2\\\\Ans.\ x=-1\ \ \ and\ \ \ y=5\ \ \ and\ \ \ z=2
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