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3 years ago

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The volume of a cone varies jointly as the square of its radius and its height. if the volume of a cone is 99piπ cubic inches wh

en the radius is 3 inchesinches and the height is 3 inches, find the volume of a cone when the radius is 4 inchesinches and the height is 9 inches.

1 answer:

tatyana61 [14]3 years ago

7 0

Any answer choices ?

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The staff at the Arcola Country Club prepares tables for a wedding reception. They are able to prepare 6 tables in 45 minutes. H

TiliK225 [7]

24

Multiply 6 and 4 to get 24

They will be able to prepare 24 tables

5 0

2 years ago

A bucket is leaking. After 3 hours the bucket has leaked 3/4 of an ounce. How many ounces per hour is the bucket leaking?

Bogdan [553]

The bucket leaks 1/4 ounce per hour. Because the numerator is 3 and it took 3 hours, you can give 1/4 to every hour (3/4 divided by 3).

6 0

2 years ago

Write in slope-intercept form an equation of the line that passes through the points (−1,12) and (1,2).

zzz [600]

Answer:

$y=-5x+7$

Step-by-step explanation:

step 1

Find the slope

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

the points (−1,12) and (1,2)

substitute

$m=\frac{2-12}{1+1}$

$m=\frac{-10}{2}$

$m=-5$

step 2

we know that

The equation of the line in slope intercept form is equl to

$y=mx+b$

where

m is the slope

b is the y-intercept

we have

$m=-5$

$point\ (1,2)$

substitute in the linear equation and solve for b

$2=-5(1)+b$

$b=2+5=7$

therefore

$y=-5x+7$

4 0

2 years ago

The angle of depression from the top of a cruise ship to the top of a sailboat is 22. Sitting above water, the cruise ship is 23

dusya [7]

Answer:

The distance between the cruise ship and the sail boat is 517 feet.

Step-by-step explanation:

The cruise ship is 236 feet tall, and the sailboat is 236 tall; this means the distance between the top of the cruise ship and the top of the sail boat is

236 feet - 27 feet = 209 feet.

We also know that the angel of depression from the top of the cruise ship to the bottom of the cruise ship is 22°. This forms a right triangle as shown in the figure attached.

Now from trigonometry we get:

$tan \: \theta = \dfrac{209}{d}$

$d= \dfrac{209}{tan\:\theta }$

$\boxed{d=517ft}$

The distance between the cruise ship and the sailboat is 517 feet.

3 0

3 years ago

Please assist me with this problem: part 11

Lady bird [3.3K]

Answer:

a² = b² -w² +2wx

Step-by-step explanation:

The algebra is pretty straightforward. Expand the expression in parentheses and add x².

b² -(w -x)² = e² = a² -x²

b² -(w² -2wx +x²) = a² -x² . . . . . expand the square

b² -w² +2wx -x² = a² -x² . . . . . . distribute the minus sign

b² -w² +2wx = a² . . . . . . . . . . . . add x²

4 0

2 years ago