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Vanyuwa [196]
3 years ago
11

The diagram shows the floor plan of a hotel lobby. Carpet costs $3 per square foot. How much will it cost to carpet the lobby?

Mathematics
2 answers:
ValentinkaMS [17]3 years ago
4 0

Answer:

It will cost $ 3348 to carpet the lobby.

Step-by-step explanation:

Refer the attached figure

AB divides the figure into two congruent trapezium

Height of trapezium = 15.5 feet

Parallel sides = 30 feet and 42 feet

Area of one trapezium = \frac{1}{2} \times \text{Sum of parallel sides} \times Height

Area of one trapezium = \frac{1}{2} \times (30+42) \times15.5

                                      = 558 ft^2

So, Area of both trapeziums = 558 \times 2 = 1116 ft^2

So, Total Area of the floor is 1116 sq.feet.

Cost of carpet of 1 sq.ft. = $3

Cost of carpet of 1116 sq.ft. = 1116 \times 3 =3348

Hence it will cost $ 3348 to carpet the lobby.

pickupchik [31]3 years ago
3 0
If you were to take both halves of the carpet and place them on top of each other you can see that the two triangle sections would cover each over up and fill in to make a rectangle. So first, lets compute the size of the middle section, then we will compute the size of the end pieces.

The center section of the carpet is 30 ft x 31 ft = 930 sq ft

The ends of the carpet are 12 ft x 15.5 ft = 186 sq ft

Since there are two side to the carpet like this we multiply this by 2
186 * 2 = 372 sq ft

Adding these two values together gives 

930 + 372 = 1302 sq ft
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Can Someone please help me with this please please please
jasenka [17]

Answer:

About 5.5, but it is technically closer to 5.6 so I am not entirely sure

Step-by-step explanation:

Since EB and DC are parallel, triangles ABE and ACD are similar by AA. Therefore:

\dfrac{x}{10}=\dfrac{10}{18} \\\\\\x=10\cdot \dfrac{10}{18}\approx 5.5

Hope this helps!

4 0
4 years ago
Can someone help me with this? I need to find the points of discontinuity/limits for each of these. I think one point is 4, but
Debora [2.8K]
The answers are shown in the attached image

-------------------------------------------------------------------------

Explanation:

Set the denominator x^4-8x^3+16x^2 equal to zero and solve for x

x^4-8x^3+16x^2 = 0
x^2(x^2-8x+16) = 0
x^2(x-4)^2 = 0
x^2 = 0 or (x-4)^2 = 0
x = 0 or x-4 = 0
x = 0 or x = 4

The x values 0 and 4 make the denominator zero

These x values lead to asymptote discontinuities because the numerator 8x-24 = 8(x-3) has no common factors which cancel with the denominator factors.

There are two vertical asymptotes

Let's see what happens when we plug in a value to the left of x = 0, say x = -1, we'd get
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(-1) = (8(-1)-24)/((-1)^4-8(-1)^3+16(-1)^2)
f(-1) = -1.28
So as x gets closer and closer to x = 0 from the left side, the f(x) is heading to negative infinity

Now plug in some value to the right of x = 0. I'm going to pick x = 1
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(1) = (8(1)-24)/((1)^4-8(1)^3+16(1)^2)
f(1) = -1.78 (approximate)
So as x gets closer and closer to x = 0 from the right side, the f(x) is heading to negative infinity

Overall, as x approaches 0 from either the left or right side of x = 0, the y value is heading off to negative infinity

---------------------

Repeat for values to the left and right of x = 4
We can't use x = 1 as it turns out that x = 3 is a root
But we can use something like x = 3.5 to find that...
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(3.5) = (8(3.5)-24)/((3.5)^4-8(3.5)^3+16(3.5)^2)
f(3.5) = 1.31 approx
So as x gets closer to x = 4 from the left, y is getting closer to positive infinity

Plug in x = 5 to find that
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(5) = (8(5)-24)/((5)^4-8(5)^3+16(5)^2)
f(5) = 0.64
which has the same behavior as the left side

So overall, as we approach x = 4, the y value is heading off to positive infinity

Again everything is summarized in the image attachment

Note: you could make a table of more values but they would effectively say what has already been said. It would be redundant busy work. However, its always good practice for function evaluation. 

6 0
3 years ago
If each foot of water in a lake screens out 60% of the light above, what percent of the light passes through 5 feet of water?
BartSMP [9]
The amount of light passing through each foot the water in the lake = 100% - 60% = 40%
The percent of light passing through 5 feet of water = 0.4^5 = 0.01024 = 1.02%
8 0
3 years ago
The distance of one light-year is approximately 9,500,000,000,000 kilometers. What is this distance in scientific notation?
zhenek [66]

Answer:

9.5*10^12 km

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find the coordinates of the midpoint of a segment having the given endpoints.
inysia [295]

Answer:

A. (1.55, 2)

Step-by-step explanation:

The formula to apply when finding the midpoint of a segment where the coordinates of the end points are given is;

midpoint=(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )

where (x₁,y₁) and (x₂,y₂) are the coordinates of the end points

Given;

x₁= -0.4 ,y₁=2.5,  x₂=3.5, y₂=1.5 then applying the formula for midpoint

=(\frac{-0.4+3.5}{2} ,\frac{2.5+1.5}{2} )\\\\\\=(\frac{3.1}{2} ,\frac{4.0}{2} )\\\\\\=(1.55,2.0)

3 0
3 years ago
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