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MrRissso [65]
3 years ago
6

What is the value of the function, f(x)=x^2-5x when x=-5 ?

Mathematics
1 answer:
bulgar [2K]3 years ago
3 0

Answer:

f(-5) = 50

Step-by-step explanation:

Simply plug in -5 for <em>x </em>into the function:

f(-5) = (-5)² - 5(-5)

f(-5) = 25 + 25

f(-5) = 50

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The Roberts family is shopping for a new vehicle. They are considering a minivan or an SUV. Each vehicle has three models; stand
azamat
I believe the answer is 30.
8 0
3 years ago
Read 2 more answers
The table below shows 10 data values:
andrezito [222]
It would be d , because the lowest number which is your (min) is 72 the highest number which is your (max) is 93 . Your median would be 85 because you would add 84 & 86 and in result you would get 170 then you would divide by 2 and get 85 . Your Q1 would be 76 and your Q3 would be 91 , there is 10 numbers in total separate them (72,74,76,83,84) and (86,89,91,92,93) then find the middle number in each

Hope this helps !
7 0
2 years ago
Ben, Tim, and Sam have to do a certain job. Ben can finish the job in 5 hours. Tim can finish the job in 6 hours. Sam can finish
Brut [27]

x is 7.5 hours

Step-by-step explanation:

Ben, Tim, and Sam have to do a certain job

  • Ben can finish the job in 5 hours
  • Tim can finish the job in 6 hours
  • Sam can finish the job in x hours
  • The three of them can finish the job in 2 hours if they work together

We need to find x

∵ Ben can finish the job in 5 hours

∴ The rate of Ben = \frac{1}{5}

∵ Tim can finish the job in 6 hours

∴ The rate of Tim = \frac{1}{6}

∵ Sam can finish the job in x hours

∴ The rate of Sam = \frac{1}{x}

They will working together to finish the job in two hours, that means the sum of their rate is equal to 1/2

∵ They can finish the job in 2 hours if they work together

∴ \frac{1}{5}+\frac{1}{6}+\frac{1}{x}=\frac{1}{2}

To add the fractions find the LCM for all denominators to make all fractions with same denominators

∵ The LCM of 5, 6 ans x is (5 × 6 × x) = 30 x,

- Divide it by each denominator to find the new numerators

∵ 30 x ÷ 5 = 6 x , 30 x ÷ 6 = 5 x , 30 x ÷ x = 30

- Change all the denominators to 30 x and then write the new

   numerators of each fraction

∴ \frac{6x}{30x}+\frac{5x}{30x}+\frac{30}{30x}=\frac{1}{2}

Add the numerators and put the sum over 30 x

∵ \frac{11x+30}{30x}=\frac{1}{2}

- By using cross multiplication

∴ 2(11 x + 30) = 1(30 x)

- Simplify the both sides

∴ 22 x + 60 = 30 x

- Subtract 22 x from both sides

∴ 60 = 8 x

- Divide both sides by 8

∴ 7.5 = x

∴ The value of x is 7.5 hours

x is 7.5 hours

Learn more:

You can learn more about the word problems in brainly.com/question/10712420

#LearnwithBrainly

5 0
3 years ago
Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10
zvonat [6]

The approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

<h3>What is depreciation?</h3>

Depreciation is to decrease in the value of a product in a period of time. This can be given as,

FV=P\left(1-\dfrac{r}{100}\right)^n

Here, (<em>P</em>) is the price of the product, (<em>r</em>) is the rate of annual depreciation and (<em>n</em>) is the number of years.

Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10%.

Suppose the original price of the first car is x dollars. Thus, the depreciation price of the car is 0.6x. Let the number of year is n_1. Thus, by the above formula for the first car,

0.6x=x\left(1-\dfrac{10}{100}\right)^{n_1}\\0.6=(1-0.1)^{n_1}\\0.6=(0.9)^{n_1}

Take log both the sides as,

\log 0.6=\log (0.9)^{n_1}\\\log 0.6={n_1}\log (0.9)\\n_1=\dfrac{\log 0.6}{\log 0.9}\\n_1\approx4.85

Now, the second car depreciates at an annual rate of 15%. Suppose the original price of the second car is y dollars.

Thus, the depreciation price of the car is 0.6y. Let the number of year is n_2. Thus, by the above formula for the second car,

0.6y=y\left(1-\dfrac{15}{100}\right)^{n_2}\\0.6=(1-0.15)^{n_2}\\0.6=(0.85)^{n_2}

Take log both the sides as,

\log 0.6=\log (0.85)^{n_2}\\\log 0.6={n_2}\log (0.85)\\n_2=\dfrac{\log 0.6}{\log 0.85}\\n_2\approx3.14

The difference in the ages of the two cars is,

d=4.85-3.14\\d=1.71\rm years

Thus, the approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

Learn more about the depreciation here;

brainly.com/question/25297296

4 0
2 years ago
Divide £2400 into the ratio 5:7
sergiy2304 [10]

Answer:

£1000, £1400

Step-by-step explanation:

Sum the parts of the ratio 5 + 7 = 12 parts

Divide the amount by 12 to find the value of one part of the ratio.

£2400 ÷ 12 = £200, thus

5 parts = 5 × £200 = £1000

7 parts = 7 × £200 = £1400

7 0
3 years ago
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