Let , coordinate of points are P( h,k ).
Also , k = 3h + 1
Distance of P from origin :
![d=\sqrt{h^2+k^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7Bh%5E2%2Bk%5E2%7D)
Distance of P from ( -3, 4 ) :
![d=\sqrt{(h+3)^2+(k-4)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28h%2B3%29%5E2%2B%28k-4%29%5E2%7D)
Now , these distance are equal :
![h^2+(3h+1)^2=(h+3)^2+(3h+1-4)^2\\\\h^2+(3h+1)^2=(h+3)^2+(3h-3)^2](https://tex.z-dn.net/?f=h%5E2%2B%283h%2B1%29%5E2%3D%28h%2B3%29%5E2%2B%283h%2B1-4%29%5E2%5C%5C%5C%5Ch%5E2%2B%283h%2B1%29%5E2%3D%28h%2B3%29%5E2%2B%283h-3%29%5E2)
Solving above equation , we get :
![P=(\dfrac{16}{21},\dfrac{23}{7})](https://tex.z-dn.net/?f=P%3D%28%5Cdfrac%7B16%7D%7B21%7D%2C%5Cdfrac%7B23%7D%7B7%7D%29)
Hence , this is the required solution.
Answer:
Hope this helps :)
Step-by-step explanation:
15
(3^5)÷(3^5)
Simplify 3^5
243÷243
1
(3^5)÷(3^5)
3^5/3^5=3^5-5
3^5-5
3^5-5= 1
1
Formula: x^a/x^b=x^a-b
16
2^10/2^10
Cancel out 2^10
1
2^10/2^10
2^10/2^10=2^10-10
2^10-10
2^10-10=1
1
Formula: x^a/x^b=x^a-b
17
x^7/x^7x≠0
x≠0
18
(4x+2y)5÷(4x+2y)^5(4x+2y) ≠ 0
5/(4x+2y)^3 ≠ 0
5 ≠ 0
≠ =-y/2
19
No solution
20
p^4/p^4p ≠ 0
p≠ 0
no solution
Answer:
On Tuesday
3/4 + 3/4 = 3/2 = 1 1/2 = 1.5
On Wednesday
2/4 + 1 1/4 = 7/4 = 1 3/4 = 1.75
Then we subtract
1.75 - 1.5 = 0.25
Answer:
I think that in the first 2 boxes its 2 i dont know for the rest though,
Step-by-step explanation:
brainky said "dont say such words here, I'm literally saying nothing rude
Answer:
-2
Step-by-step explanation:
Equation of slope intercept form
y = (slope × x) + y intercept