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Alex Ar [27]
3 years ago
14

Lo

Mathematics
1 answer:
mylen [45]3 years ago
7 0

Hello thee i hope you are having good day :) Your Question: 15-foot piece of string is cut into two pieces so that the longer piece is 3 feet longer than twice the shorter piece. If the shorter piece is x feet long, find the lengths  of both pieces.

so firstly you would do  L = 3 + 2x  S = x  X + (3 + 2x) = 15  X + 3 + 2x = 15

3x + 3 = 15  then you would take away that 3x = 15 - 3  this would equal 12 so x = 4 and then add it 3+ 2x = 3+2 (4) = 3 + 8 = 11   Short piece is 4 feet  Long piece is 11 feet.

Hopefully that helps you ❤

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Answer:

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Step-by-step explanation:

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4 years ago
An object is launched from a launching pad 208 ft. above the ground at a velocity of 192ft/sec. what is the maximum height reach
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Answer:

h(x) = -16x² + 192x + 208

784ft

6 sec

13 sec

Step-by-step explanation:

a)

h(x) = -16x² +vx + h_{o}

here v represent velocity

         h_{o} represent initial height of launch

       

h(x) = -16x² + 192x + 208

b)

h(x) = -16x² + 192x + 208

here a = -16

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e)

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Factors

1x * -13x = -13

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Factorised form

x² - 12x - 13 = 0

x² + x - 13x - 13 = 0

x(x+1) -13(x+1) = 0

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Since time can not be negative so we will reject x = -1  

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