Answer:
Please check the explanation.
Step-by-step explanation:
Given the vector
v = 6i + 2√3j
The Magnitude of a vector:
![\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}](https://tex.z-dn.net/?f=%5Cmathrm%7BApply%5C%3Aradical%5C%3Arule%7D%3A%5Cquad%20%5Csqrt%5Bn%5D%7Bab%7D%3D%5Csqrt%5Bn%5D%7Ba%7D%5Csqrt%5Bn%5D%7Bb%7D)
The Direction of a vector:
tan Ф = y/x
y=2√3
x = 6
tan Ф = y/x
= 2√3 / 6
= √3 / 3
Answer:
B. C. and E.
Step-by-step explanation:
Answer:
C is the answer
Step-by-step explanation:
pls add me on brainlist
Answer:
Im not sure tbh, but go to this website called Symbolab, and just type it in and it gives you a step by step process om how to solve it! ( :
Step-by-step explanation:
S = a*((1 - r^(n+1))/(1-r))
S = 1*((1 - 2^(7+1))/(1-2))
S = 1*((1 - 2^8)/(1-2))
S = 1*((1 - 256)/(1-2))
S = 1*((-255)/(-1))
S = 255
So 1+2+4+8+...+128 = 255
