A gardener made a scale drawing of a lawn with a scale factor of 1:10. The

Mathematics

1 answer:

frozen [14]2 years ago

5 0

Answer:

The length is 35 inches and the width is 15 inches.

Step-by-step explanation:

First work of the real length of the field. Given is the ratio of drawing to original and the dimensions of the drawing. so in real life the lawn measures 70 inches in length and 30 inches in width.

Now, we have to divide this in the ratio 1:2, which gives

The length of 35 inches and the width of 15 inches.

Hope this helps

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Which is less: (-20)+10 or 20+(-35)? Explain your answer.

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Answer:

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Step-by-step explanation:

(-20) + 10 = -10

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The circumference of the ellipse approximate. Which equation is the result of solving the formula of the circumference for b?

Serhud [2]

Answer:

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

Step-by-step explanation:

Given - The circumference of the ellipse approximated by $C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }$ where 2a and 2b are the lengths of 2 the axes of the ellipse.

To find - Which equation is the result of solving the formula of the circumference for b ?

Solution -

$C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }\\\frac{C}{2\pi } = \sqrt{\frac{a^{2} + b^{2} }{2} }$

Squaring Both sides, we get

$[\frac{C}{2\pi }]^{2} = [\sqrt{\frac{a^{2} + b^{2} }{2} }]^{2} \\\frac{C^{2} }{(2\pi)^{2} } = {\frac{a^{2} + b^{2} }{2} }\\2\frac{C^{2} }{4(\pi)^{2} } = {{a^{2} + b^{2} }$