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LuckyWell [14K]
2 years ago
5

Slope from two points: (-15, 2) and (-3, 18)

Mathematics
2 answers:
Luba_88 [7]2 years ago
7 0
The answer is 4/3 have a good day
Lana71 [14]2 years ago
3 0

Answer:

The answer to your question is 4/3

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Gianna used 11.9 yards of fabric to make 7 same-sized aprons for the cooking club. How much fabric did Gianna use per apron?
docker41 [41]

Answer:

Step-by-step explanation:

11.9 divided by 7 = 1.7

She uses 1.7 yards per apron

5 0
2 years ago
BRAINLIEST IF CORRECT
stellarik [79]
The answer is C. f(x) = 0.05 
4 0
3 years ago
Read 2 more answers
a wrestler is weighing in for their match this evening. their normal weight is 168 pounds, but that weight can vary by as much a
Natalija [7]

<em>Introduction </em>

<em>Wrestling is a wonderful activity with many advantages for the student-athlete. It is a sport that is highly </em>

<em>competitive, exciting and satisfying. It is a sport that provides for individual and team competition. It is - </em>

<em>and should be - fun. Unfortunately, the practice of losing weight by not eating, restricting fluid intake and </em>

<em>over-exercising reduces the sport's fun. This information is presented to help clear up misconceptions </em>

<em>regarding wrestling and weight loss. I also hope to give some guidance to those who desire to manage </em>

<em>their weight properly in preparation for and during the wrestling season. </em>

<em>History and Stigma </em>

<em>For too long, the wrestling community has unthinkingly accepted the myth that to be a good wrestler, you </em>

<em>must cut weight. The generally accepted thinking is something like this: if your natural weight is 135 </em>

<em>pounds, you may be a good wrestler at 135 pounds. But if you wrestle at 130 pounds, you'll be a better </em>

<em>wrestler. And if you can make it down to 125, you'll be a state champion. No facts support that widely held </em>

<em>view, yet wrestlers and parents subscribe to that faulty reasoning. Looking further back, many remember </em>

<em>the days that losing excessive weight was a specific practice and expectation among wrestlers. It was </em>

<em>supposed to teach sacrifice, commitment, and the idea of “No Pain, No Gain.” </em>

<em>Regardless of the current attitude of the majority of the wrestling community, the stigma that an unhealthy </em>

<em>loss of weight is a requirement of wrestling among outside observers sticks. The Virginia High School </em>

<em>League has followed national guidelines to establish rules that encourage healthy weight management </em>

<em>among wrestlers. </em>

<em>Current Regulations </em>

<em>Preseason weight certification is accomplished with three steps. The first is determining each wrestler’s </em>

<em>body fat percentage using skin fold calipers. Next, the wrestler completes a hydration test, to insure </em>

<em>against a dehydrated weight measurement, and the wrestler weighs in. The third step is the calculation of </em>

<em>the wrestler’s minimum wrestling weight based on 7% body fat for males and 12% for females. The </em>

<em>wrestler may not wrestle at a weight class below his minimum weight during the season. The wrestler is </em>

<em>also restricted from losing more then 1.5% body weight loss per week (official weigh-ins at certification, </em>

<em>matches, and tournaments are used for this calculation). A one-pound per month growth allowance is </em>

<em>provided to allow for the natural growth of this age group. The VHSL advises, and we have instituted, </em>

<em>daily weigh-ins before and after practice to monitor weight-loss and dehydration. </em>

<em>Additionally, the National Federation of State High School Associations has adopted several other rules to </em>

<em>guide coaches and wrestlers while managing their weight. Wrestlers are discouraged from wrestling at a </em>

<em>weight class more then one weight class above their certified weight. </em>

5 0
3 years ago
Help me guys please !
neonofarm [45]

Answer:

<em>Tim </em><em>will </em><em>get </em><em>£</em><em> </em><em>8</em>

<em>Sam </em><em>will </em><em>get </em><em>£</em><em> </em><em>3</em><em>2</em>

<em>Solution,</em>

<em>let </em><em>the </em><em>ratios </em><em>be </em><em>x </em><em>and </em><em>4</em><em>x</em>

<em>x + 4x = 40 \\ or \: 5x = 40 \\ or \: x =  \frac{40}{5}  \\ x = 8 \\ replacing \: value \\ 4x \\  = 4 \times x \\  = 4 \times 8 \\  = 32</em>

<em>hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em>

8 0
3 years ago
Read 2 more answers
Which of these strategies would eliminate a variable in the system of equations? \begin{cases} 6x + 5y = 1 \\\\ 6x - 5y = 7 \end
IRISSAK [1]

Answer:

x = 0.667 and y = -0.6

Step-by-step explanation:

Given that,

6x + 5y = 1 ....(1)

6x - 5y = 7 ...(2)

We need to solve the above equations.

Subtract equations (1) and (2)

6x + 5y -(6x - 5y) = 1-7

6x+5y-6x+5y = -6

10y=-6

y = -0.6

Put the value of y in equation (1).

6x + 5(-0.6) = 1

6x = 1-5(-0.6)

6x = 4

x = 0.667

Hence, first step is to subtract equation (1) and (2) then put the value of y in equation (1).

3 0
2 years ago
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