28x + 44y = 964.40
21x + 33y = 723.30
Let's multiply the first equation by 4 and the second by -4
84x + 176y = 3857.6
-84x - 132y = -2893.2
Add the equations together.
0 + 44y = 964.4
Simplify
44y = 964.4
Divide both sides by 44
y = 964.4/44
Since we have the value of y, let's plug 964.4/44 into y for the first equation.
28x + 44(964.4/44) = 964.40
Simplify the left side
28x + 964.4 = 964.4
Subtract 964.4 from both sides
28x = 0
Divide both sides by 0
x = 0
In conclusion,
y = 964.4/44
x = 0
Answer:
x= 48 and PMO= 55
Step-by-step explanation:
PMO= LMO so 55= x+7
x+7=55
-7 -7
x=48
Pmo = x+7 so (48)+7 = 55
Answer:
1/20
Step-by-step explanation:
hope this helps
Answer:
Part a) The slant height is 
Part b) The lateral area is equal to 
Step-by-step explanation:
we know that
The lateral area of a right pyramid with a regular hexagon base is equal to the area of its six triangular faces
so
![LA=6[\frac{1}{2}(b)(l)]](https://tex.z-dn.net/?f=LA%3D6%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28l%29%5D)
where
b is the length side of the hexagon
l is the slant height of the pyramid
Part a) Find the slant height l
Applying the Pythagoras Theorem

where
h is the height of the pyramid
a is the apothem
we have


substitute



Part b) Find the lateral area
![LA=6[\frac{1}{2}(b)(l)]](https://tex.z-dn.net/?f=LA%3D6%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28l%29%5D)
we have


substitute the values
![LA=6[\frac{1}{2}(6)(3\sqrt{2})]=54\sqrt{2}\ units^{2}](https://tex.z-dn.net/?f=LA%3D6%5B%5Cfrac%7B1%7D%7B2%7D%286%29%283%5Csqrt%7B2%7D%29%5D%3D54%5Csqrt%7B2%7D%5C%20units%5E%7B2%7D)