This question is based on prime factorization method.
As given there are 12 peaches and 18 nectarines
Factors of 12 are : 2,3,4,6 and 12
Factors of 18 are : 2,3,6,9 and 18
As mentioned, fruits are divided into the same number of equal groups, so the groups can be formed as-
1. 6 groups of peaches with 2 in each and 6 groups of nectarines with 3 in each,
2. 3 groups of peaches with 4 in each and 3 groups of nectarines with 6 in each.
3. 2 groups of peaches with 6 in each and 2 groups of nectarines with 9 in each.
Answer:
21
Step-by-step explanation:
You have to multiply 3 and 7 to get 21.
The value is -3.2. Hope it helps!
7. tails, odd, 4
P(tails) = 1/2
P(odd) = 3/6 = 1/2
P(4) = 1/6
P(tails then odd then 4) = (1/2)×(1/2)×(1/6) = 1/24 ≈ 0.041666
Answer: 1/24, 4.2%
8. tails, 6 or 1, 3
P(6 or 1) = 2/6 = 1/3
P(3) = 1/6
P( tails, 6 or 1, 3) = (1/2)(1/3)(1/6) = 1/36 ≈ 0.027777
Answer: 1/36, 2.8%
9. heads, not 2, even
P(heads) = 1/2
P(not 2) = 5/6
P(even) = 1/2
P(heads, not 2, even) = (1/2)(5/6)(1/2) = 5/24 ≈ 0.208333
Answer: 5/24, 20.8%
Answer:
Subtract 5 from both sides.
Step-by-step explanation: