Answer:
#1. Identity #2. 0 #3. No solution
Step-by-step explanation:
#1.
5y + 2 = (1/2)(10y+4)
5y + 2 = 5y + 2
This would be identity as the equation of the left and right are the same. This is not to be confused with no solution(explained below).
#2.
0.5b + 4 = 2(b+2)
0.5b + 4 = 2b + 4
0.5 b - 2b = 0
b = 0
#3.
-3x + 5 = -3x + 10
This equation has no solution because when you try to bring the -3x to one side, the x variable itself gets eliminated. So, how is it different from identity? Well in the first equation, it is true that when we try to bring the 5y one side it eliminates the y variable, however, that is also true for the constants(since if we try to bring the 2 to one side, it will be 2-2 which will equal 0, thus eliminating each other), but in this case, even if we remove the x, the constants will not equal 0, thus it will have no solution.
Answer:i need more info to answer this question
Step-by-step explanation:
52/2= 26
The quotient is 26, but there are no remainder.
Hope this helps!
The gcf of 15 and 70 is 5
(1, 1), 5 + 2 = 7, not that hard!
