All categories

4 years ago

NEED HELP PLEASE.....WILL GIVE 5 STARS!.... It is EASY BUT I DO NOT GET HOW TO DO IT!

Mathematics

1 answer:

zmey [24]4 years ago

7 0

7.
irt = simple Interest we can fill in what we know so $500 * I * 20 = $250 than we solve for I so $250 / 500 = 0.5 than 0.5 / 20 = 0.025

8. Irt = simple interest fill it in 850 * I * 10 = $255 and then solve for I 255 / 850 = 0.3 than 0.3 / 10 = 0.03

9. Irt = simple interest 1200 * I * 15 = $720 and than solve for I so 720 / 1200 = 0.6 and then 0.6 / 15 = 0.04

You might be interested in

558 cups of water fill 412 identical water bottles. How many cups fill each bottle ?

Elan Coil [88]

Answer:

5/4 cups fill each bottle

Step-by-step explanation:

5 5/8=45/8

4 1/2=9/2

Step by Step:

------------------

(45/8)/(9/2)

(45/8)(2/9)

(45/4)(1/9)

45/36

5/4

8 0

3 years ago

Work out 2/21 + 6/7 Give your answer in its simplest form.

olganol [36]

Answer:

2/21+6/7 = 20/21

Step-by-step explanation:

2/21+6/7

=2/21+(6*3/7*3)

=2/21+18/21

=20/21

Hope this helps! Comment any questions <3

4 0

2 years ago

Read 2 more answers

Help me please anyone

OverLord2011 [107]

5 km = 5000 M = 500000 Cm

8 0

3 years ago

Laura retired from her job recently, and she has saved about $427,595.00 over the course of her career. She plans to withdraw

Rzqust [24]

Answer:

24 mouths have passed

Step-by-step explanation:

8 0

3 years ago

A metalworker has a metal alloy that is 15% copper and another alloy that is 75% copper. How many kilograms of each alloy shou

lisov135 [29]

48 kilograms of 15 % copper is combined with 72 kilograms of 75 % copper to create 120 kg of a 51% copper alloy

Solution:

Let "x" be the kilograms of 15 % copper

Then, (120 - x) be the kilograms of 75 % copper

Then, according to question,

"x" kilograms of 15 % copper is combined with (120 - x) kilograms of 75 % copper to create 120 kg of a 51% copper alloy

Thus we frame a equation as:

15 % of x + 75 % of (120 - x) = 51 % of 120

Solve the equation for "x"

$15 \% \times x + 75 \% \times (120-x) = 51 \% \times 120\\\\\frac{15}{100} \times x + \frac{75}{100} \times (120-x) = \frac{51}{100} \times 120\\\\0.15x + 0.75(120-x) = 0.51 \times 120\\\\0.15x + 90 - 0.75x = 61.2\\\\0.6x = 90 - 61.2\\\\0.6x = 28.8\\\\Divide\ both\ sides\ by\ 0.6\\\\x = 48$

Thus 48 kilograms of 15 % copper used

Then, (120 - x) = (120 - 48) = 72

Thus, 72 kilograms of 75 % copper is used

4 0

3 years ago