0.08 and 0.4 as fractions in simplest form

Given that these simultaneous equations

Tatiana [17]

The value of k is $(3\sqrt{ 10})/2$

<h3>How to solve the simultaneous equation?</h3>

Given:

x-y=k.............(eq i)

2x²+y²-15..............(eq ii)

We would make y the subject formula in eq ii

2x²+y²-15= 0

2x² + y²= 15

y²= 15-2x²

y= $\sqrt{15-2x^2}$ ...........(eq iii)

Substitute the value of y into eq i

x-( $\sqrt{15-2x^2}$ = k

x- ( $\sqrt{15} - 2x$ = k

k= $(3\sqrt{ 10})/2$

Read more about simultaneous equations here:

brainly.com/question/16863577

#SPJ1

3 0

2 years ago

Tammy is at the dentist's office waiting on her appointment. She notices that the 6-inch-long minute hand is rotating around the

Elena L [17]

PART 1:55-21=35
35/60=.58333
360×.58333 =210 DEGREES
210*pi/180 = 3.665 RADIANS

PART 2: (pi) x 2r x .58333
3.14 x 12 x .58333 = 21.98 in

PART 3: 5π inches = 5 x 3.14 = 15.708 inches / 6 in radius = 2.618 radians

PART 4: 2.618 radians * 180/pi = 150° 
 x coordinate = 6(cos 150°) = -5.196 
 y coordinate = 6(sin 150°) = 3 
 the coordinates would be (-5.196, 2)

7 0

3 years ago

Read 2 more answers

Can someone explain to me in words how to do this problem 3x+122=22x-11

inn [45]

When you have this type of problem, you need to combine the like-terms and isolate the variable.

3x + 122 = 22x - 11

Add 11 to both sides to get rid of it

3x + 122 + 11 = 22x - 11 + 11 (-11 + 11=0)

3x + 133 = 22x

Then you would bring the 3x to the other side, so subtract 3x from both sides

3x + 133 = 22x