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snow_tiger [21]
4 years ago
9

When comparing prices for activities at a local recreation center, you notice that the center charges different prices on differ

ent days of the week. For example, riding a go-kart costs $10 on Saturday and Sunday and $5 on Monday through Friday.
Is the cost a function of the activity type? Explain why or why not.
Mathematics
2 answers:
Artemon [7]4 years ago
6 0
No, because the activity type is not changing, the only variable in this question (other than the price) is the day of the week, So the price is a function/is affected by the day of the week rather than the activity type.
grigory [225]4 years ago
5 0

Answer:

Step-by-step explanation:

Sample Answer: The activity type would be the input and the cost would be the output. Because there are two different costs for the same activity, this would not be a function.

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Combine the terms by multiplying into a single fraction.

\bf{\dfrac{5}{2}x-7=\dfrac{3}{4}x+14   }

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\bf{\dfrac{5x}{2}-7=\dfrac{3}{4}x+14   }

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\bf{\dfrac{5x-14}{2}=\dfrac{3x+4\cdot14}{4}   }

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\bf{10x-28+28=3x+56+28 }

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\bf{10x-3x=3x+84-3x }

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Divide both sides by the same factor.

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\bf{x=12 \ \ \ === > \ \ \ Answer}

↓

<h3>Verification</h3>

Let x=12.

  1. \bf{\dfrac{5}{2}\times12-7=\dfrac{3}{4}\times12+14   }
  2. \bf{\dfrac{5\times12}{2}-7=\dfrac{3}{4}\times12+14   }
  3. \bf{\dfrac{60}{2}-7=\dfrac{3}{4}\times12+14   }
  4. \bf{30-7=\dfrac{3}{4}\times12+14   }
  5. \bf{30-7=\dfrac{3\times12}{4}+14   }
  6. \bf{30-7=\dfrac{36}{4}+14   }
  7. \bf{30-7=9+14   }
  8. \bf{23=9+14 }
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