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BARSIC [14]
3 years ago
13

Which strategy would you use to find 2+8 ? Explain how you decided

Mathematics
2 answers:
pogonyaev3 years ago
4 0

1. Strategy I would use

Let me show you an strategy:

<u>Break apart strategy:</u>

The strategy of break apart numbers (Place Value) consists in the decomposition or separation of numbers. We can break both numbers down to place value and add each, starting with the largest or keep one number intact and only break second number down by place value and adding each place. Anyway, using this strategy we have:

2 + 8 = ?

2 breaks into 1 plus 1 (1 + 1), 8 breaks into 4 plus 4 (4 + 4), so by associative property:

(1+4)+(1+4) = 5+5=10

2. Explain how I decided.

This strategy is good to add larger numbers. In this way, we may break larger numbers up into hundreds, tens, ones, then add. This is an easy way to find additions.

SVETLANKA909090 [29]3 years ago
4 0
<span> What we can do for this case is rewrite both numbers.
 We have then:
</span> 8 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1&#10;&#10;2 = 1 + 1<span>
 With the numbers rewritten in this way, to find the sum of 8 + 2 what we must do is add the number of times the number 1 is repeated.
 We have then:
</span> 8 + 2 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1&#10;&#10;8 + 2 = 10<span>
 Answer:
 8 + 2 = 10</span>
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Answer:

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Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

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The upper limit of this interval is:

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4 0
3 years ago
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