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3 years ago

96 ÷ 42 + (25 x 2) - 15 - 3=? I need help with my math

1 answer:

7 0

Pemdas
so do parenthaseese first
work inside then out
(25 times 2)
(50)
now we have
96/42+(50)-15-3=?

start from the begining again of the equation (left) now we do division
96/42=16/7

now we have 16/7+(50)-15-3
start over and do addition
16/7+50=2 and 2/7+50=2+2/7+50=52 and 2/7
subtract
52 and 2/7-15=52+2/7-15=37 +2/7=37 and 2/7
then subtract 3
37 and 2/7-3=37+2/7-3=34+2/7=34 and 2/7

answer is 34 and 2/7

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Step-by-step explanation:

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4 years ago

For 0 ≤ ϴ < 2π, how many solutions are there to tan(StartFraction theta Over 2 EndFraction) = sin(ϴ)? Note: Do not include va

Black_prince [1.1K]

Answer:

3 solutions:

$\theta={0, \frac{\pi}{2}, \frac{3\pi}{2}}$

Step-by-step explanation:

So, first of all, we need to figure the angles that cannot be included in our answers out. The only function in the equation that isn't defined for some angles is $tan(\frac{\theta}{2})$ so let's focus on that part of the equation first.

We know that:

$tan(\frac{\theta}{2})=\frac{sin(\frac{\theta}{2})}{cos(\frac{\theta}{2})}$

therefore:

$cos(\frac{\theta}{2})\neq0$

so we need to find the angles that will make the cos function equal to zero. So we get:

$cos(\frac{\theta}{2})=0$

$\frac{\theta}{2}=cos^{-1}(0)$

$\frac{\theta}{2}=\frac{\pi}{2}+\pi n$

$\theta=\pi+2\pi n$

we can now start plugging values in for n:

$\theta=\pi+2\pi (0)=\pi$

if we plugged any value greater than 0, we would end up with an angle that is greater than $2\pi$ so, that's the only angle we cannot include in our answer set, so: