Answer:
See below.
Step-by-step explanation:
The rocket's flight is controlled by its initial velocity and the acceleration due to gravity.
The equation of motion is h(t) = ut + 1.2 g t^2 where u = initial velocity, g = acceleration due to gravity ( = - 32 ft s^-2) and t = the time.
(a) h(t) = 64t - 1/2*32 t^2
h(t) = 64t - 16t^2.
(b) The graph will be a parabola which opens downwards with a maximum at the point (2, 64) and x-intercepts at (0, 0) and (4, 0).
The y-axis is the height of the rocket and the x-axis gives the time.
Maximum height = 64 feet, Time to maximum height = 2 seconds, and time in the air = 4 seconds.
Answer:
Option d
Step-by-step explanation:
Other options are not eligible because
a) Integers are not irrational
b)Whole numbers start from 0 and consists positive integers only.But integers consist negative integers also.
c)Natural number consists of positive integers only.
If the question had been asked as some integers are also, then options b) and c) could have been written . But in this case , it is asked every integer is also.
Thank you!
Answer:the mode is 2 1/2 because it repeats twice
Step-by-step explanation:repeats twice
Answer:
it depends how much oatmeal she has -.-
Step-by-step explanation:
JKJK I think its ten...
Answer:
The volume of cylinder is:
49806.06 ft^3
Step-by-step explanation:
We are given a right circular cylinder with:
Height(h)=![22\frac{1}{4}ft=\dfrac{89}{4}ft](https://tex.z-dn.net/?f=22%5Cfrac%7B1%7D%7B4%7Dft%3D%5Cdfrac%7B89%7D%7B4%7Dft)
and a diameter is
times it's height.
i.e.
times it height.
i.e. the diameter is given as:
![\dfrac{12}{5}\times \dfrac{89}{4}=\dfrac{267}{5}ft.](https://tex.z-dn.net/?f=%5Cdfrac%7B12%7D%7B5%7D%5Ctimes%20%5Cdfrac%7B89%7D%7B4%7D%3D%5Cdfrac%7B267%7D%7B5%7Dft.)
We know that the radius of cylinder is half the diameter.
Hence, radius(r) of cylinder is:
![\dfrac{1}{2}\times \dfrac{267}{5}\\\\=\dfrac{267}{10}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%20%5Cdfrac%7B267%7D%7B5%7D%5C%5C%5C%5C%3D%5Cdfrac%7B267%7D%7B10%7D)
The volume(V) of cylinder is given by:
![V=\pi r^2h](https://tex.z-dn.net/?f=V%3D%5Cpi%20r%5E2h)
![V=3.14\times (\dfrac{267}{10})^2\times \dfrac{89}{4}\\\\V=\dfrac{19922423.94}{400}\\\\V=49806.06ft^3](https://tex.z-dn.net/?f=V%3D3.14%5Ctimes%20%28%5Cdfrac%7B267%7D%7B10%7D%29%5E2%5Ctimes%20%5Cdfrac%7B89%7D%7B4%7D%5C%5C%5C%5CV%3D%5Cdfrac%7B19922423.94%7D%7B400%7D%5C%5C%5C%5CV%3D49806.06ft%5E3)
Hence, the volume of cylinder is:
49806.06 ft^3