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aev [14]
3 years ago
13

Use the equation y = 4x to answer the questions.

Mathematics
1 answer:
Nastasia [14]3 years ago
3 0

The slope is 4 and the Y-Intercept is 0.


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Which ratio is greater than 11/16?
OleMash [197]
3/4 is great if thats on of your answers because it was one of mine
5 0
3 years ago
X² - 6x + 4 = 0<br><br> solve and show work. ...?
ycow [4]
The answer is 3 + √5 and 3 - √5.

This is quadratic equation: x² - 6x + 4 = 0
The general quadratic equation is ax² + bx + c = 0
Our equation can be rewritten: 1x² + (-6)x + 4 = 0
So, in our equation we have: a = 1, b = -6, c = 4

Now, x can be calculated using the formula:x_{1,2}= \frac{-b+/- \sqrt{ b^{2}-4ac } }{2a}
x_{1,2} =\frac{-(-6)+/- \sqrt{ (-6)^{2}-4*1*4 } }{2*1} = \frac{6+/- \sqrt{36-16} }{2} = \frac{6+/- \sqrt{20} }{2} =\frac{6+/- \sqrt{4*5} }{2}=  \\ &#10;=\frac{6+/- \sqrt{4}* \sqrt{5}  }{2} =\frac{2*3+/- 2\sqrt{5}  }{2}= \frac{2(3+/- \sqrt{5}) }{2} =3+/- \sqrt{5}

From here:
x_{1} =3+ \sqrt{5}  \\ &#10;x_{2} =3- \sqrt{5}

6 0
4 years ago
Find the distance between these points and round to the nearest tenth.<br> (-9,3) and (9. - 3)
cluponka [151]

Answer:

You add the parts then subtract them with the old part

Step-by-step explanation:

8 0
3 years ago
I need to solve the linear equation:<br>5x-3=2x+15​
11111nata11111 [884]

Answer:

x=6

Step-by-step explanation:

5x-3=2x+15

5x-2x-3=15

3x-3=15

3x=15+3

3x=18

x=18/3

x=6

3 0
3 years ago
Please help me with this
postnew [5]

Answer:

  (c)  BC ≅ BC, reflexive property

Step-by-step explanation:

The conclusion of this proof derives from CPCTC and the SAS congruence postulate. In order for SAS to apply, corresponding sides and the angle between them must be shown to be congruent. The congruence statement ...

  ΔABC ≅ ΔDCB

tells you these pairs of sides and angles are congruent:

  • AB ≅ DC . . . . statement 2
  • ∠ABC ≅ ∠DCB . . . . statement 4
  • BC ≅ CB . . . . (missing statement 5)
  • AC ≅ DB . . . . statement 7

That is, the statement needed to complete the proof is a statement that segment BC is congruent to itself. That congruence is a result of the reflexive property of congruence.

4 0
2 years ago
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