The equation can be used to calculate the surface area of the triangular prism.
It is given that the triangular prism net showing in the figure with dimensions.
It is required to find which equation can be used to find the surface area of the triangular prism net.
<h3>What is surface area?</h3>
It is defined as the area of 3-dimensional geometry surfaces area sum which is occupying the outer area of the object.
We know the area of a rectangle = length × width
Area of the top rectangle = 13×10
Area of the middle rectangle = 12×10
Area of bottom rectangle= 5×10
The formula for finding the area of a triangle:
Area of right triangle =
Area of left triangle =
The surface area = Area of top+ Area of middle+ Area of bottom+ Area of
a right triangle+ Area of the left triangle
Thus, the equation can be used to calculate the surface area of the triangular prism.
Learn more about the surface area here:
brainly.com/question/1196953
Answer:
y = 4x
Step-by-step explanation:
If y is directly proportional to x (which is what I assume you are meaning in this question), this means that
y = kx, where k is the constant of proportionality.
To find k, we simply substitute in the given x and y values, and solve for k. i.e we to get:
8 = k x 2.
k = 8/2 = 4.
so y = 4x
Step-by-step explanation:
a)
6.9+1.1= 8
b)
9.9+2.45=12.35
c)
2.4+8.9=11.3
d)
6.37+7.7=14.07
Answer:
a.
Period = π
Amplitude = 4
b.
Maximum at: x = 0, π and 2π
Minimum at: x = π/2 and 3π/2
Zeros at: x = π/4, 3π/4, 5π/4 and 7π/4
Step-by-step explanation:
Part a:
Amplitude represents the half of the distance between the maximum point and the minimum point of the function. So the easy way to find the amplitude is: Find the difference between maximum and minimum value of the function and divide the difference by 2.
So, amplitude will be:
Therefore, the amplitude of the function is 4.
Period is the time in which the function completes its one cycle. From the graph we can see that cosine started at 0 and completed its cycle at π. After π the same value starts to repeat. So the period of the given cosine function is π.
Part b:
From the graph we can see that the maximum values occur at the following points: x = 0, π and 2π
The scale on x-axis between 0 and π is divided into 4 squares, so each square represents π/4
Therefore, the minimum value occurs at x = π/2 and 3π/2
Zeros occur where the graph crosses the x-axis. So the zeros occur at the following points: π/4, 3π/4, 5π/4 and 7π/4