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Katena32 [7]
3 years ago
5

If U = the set of odd natural numbers and B = {13, 15, 17, 19, 21, 23, . . .}, find B′.

Mathematics
2 answers:
Yuki888 [10]3 years ago
8 0

Answer:

{1,3,5,7,9,11}

Step-by-step explanation:

B' stands for the complement of B.

B' means set elements in the universe that aren't in B.

Here is the universe:

U={1,3,5,7,9,11,13,15,17,19,21,23,25,27,29,31,33,...}

(The dots mean it continues with that pattern forever and ever.)

And the elements we taking out:

B={13,15,17,19,21,23,...}

So we taking out the odd numbers from U that are odd and greater than or equal to 13. (The dots mean it continues with that pattern forever and ever.)

So B' is the set of natural odd numbers that are less than 13:

{1,3,5,7,9,11}

Elis [28]3 years ago
8 0

Answer:

B' = {1, 3, 5, 7, 9, 11}.

Step-by-step explanation:

B' is the set of the odd natural number which are not in U - that is odd numbers less than 13.

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A number greater than 40 and have 5 in the tenths place
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A number greater than 40 and have 5 in the tenth place is 50
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Gnom [1K]

Answer:

x≥5

Step-by-step explanation:

-1 ≥ x/-5

x/-5 ≤ -1

x(-1)/5 ≥ (-1) (-1)

x/5 ≥ 1

5x/5 ≥ 1 ×5

x ≥ 5

I'm not sure but I tried.

For the graph: you can draw a line about 15cm, put 0 at the start then after 5cm put 5 then 10 at 10cm and 15 at the end. At 5 put • that's the starting and go all the way to 15 and add > to show that the line continues. I'm not good at explaining but I hope it helps.

8 0
2 years ago
The probability that a rental car will be stolen is. 4. if 3500 cars are rented, what is the approximate poisson probability tha
kozerog [31]

Using the Poisson distribution, there is a 0.8335 = 83.35% probability that 2 or fewer will be stolen.

<h3>What is the Poisson distribution?</h3>

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

The parameters are:

  • x is the number of successes
  • e = 2.71828 is the Euler number
  • \mu is the mean in the given interval.

The probability that a rental car will be stolen is 0.0004, hence, for 3500 cars, the mean is:

\mu = 3500 \times 0.0004 = 1.4

The probability that 2 or fewer cars will be stolen is:

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

In which:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-1.4}1.4^{0}}{(0)!} = 0.2466

P(X = 1) = \frac{e^{-1.4}1.4^{1}}{(1)!} = 0.3452

P(X = 2) = \frac{e^{-1.4}1.4^{2}}{(2)!} = 0.2417

Then:

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.2466 + 0.3452 + 0.2417 = 0.8335

0.8335 = 83.35% probability that 2 or fewer will be stolen.

More can be learned about the Poisson distribution at brainly.com/question/13971530

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Find the algebra 5xy(2x+3xy)​
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Answer 5

Step-by-step explanation:

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