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Elodia [21]
3 years ago
5

A system of equations is shown below: 5x + 2y = 3 (equation 1) 2x − 3y = 1 (equation 2) A student wants to prove that if equatio

n 2 is kept unchanged and equation 1 is replaced with the sum of equation 1 and a multiple of equation 2, the solution to the new system of equations is the same as the solution to the original system of equations. If equation 2 is multiplied by 1, which of the following steps should the student use for the proof?
Mathematics
2 answers:
posledela3 years ago
6 0

Answer:

Student should show that the solution to the system of equations 7x - y = 4 and 2x - 3y = 1 is the same as the solution to the given system of equations.

Step-by-step explanation:

Given System of equations is 5x + 2y = 3 (equation 1) and 2x - 3y = 1 (equation 2)

Second System of equations is 2x - 3y = 1 and 7x - y = 4

How we got  7x - y = 4

Step 1: Multiply 2x - 3y = 1 by 1, we get the same 2x - 3y = 1

Step 2: Add 5x + 2y = 3 with 2x - 3y = 1

5x + 2x + 2y - 3y = 1

7x - 3y = 1

We have got second equation 7x - 3y = 1

Thus, Student should show that the solution to the system of equations 7x - y = 4 and 2x - 3y = 1 is the same as the solution to the given system of equations.


Lesechka [4]3 years ago
6 0

Answer:

I just took the test and the answer is Student should show that the solution to the system of equations 7x - y = 4 and 2x - 3y = 1 is the same as the solution to the given system of equations.

Step-by-step explanation:

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MrRissso [65]

Answer:

1. D. 20, 30, and 50

2. A. 86

3. B. 94

Step-by-step explanation:

1. To find the outliers of the data set, we need to determine the Q1, Q3, and IQR.

The Q1 is the middle data in the lower part (first 10 data values) of the data set (while the Q3 is the middle data of the upper part (the last 10 data values) the data set.

Since it is an even data set, therefore, we would look for the average of the 2 middle values in each half of the data set.

Thus:

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Q3 = (93 + 95)/2 = 94

IQR = Q3 - Q1 = 94 - 86

IQR = 8

Outliers in the data set are data values below the lower limit or above the upper limit.

Let's find the lower and upper limit.

Lower limit = Q1 - 1.5(IQR) = 86 - 1.5(8) = 74

The data values below the lower limit (74) are 20, 30, and 50

Let's see if we have any data value above the upper limit.

Upper limit = Q3 + 1.5(IQR) = 94 + 1.5(8) = 106

No data value is above 106.

Therefore, the only outliers of the data set are:

D. 20, 30, and 50

2. See explanation on how to we found the Q1 of the given data set as explained earlier in question 1 above.

Thus:

Q1 = (85 + 87)/2 = 86

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Answer:

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3 years ago
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